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Inverse and Composite Functions

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Question 15

The function h h\,h is defined such that

h(x)=x2−16 h(x) = x^2 - 16 h(x)=x2−16
a.

Find an expression for h(x+1)h(x + 1)h(x+1)

[2]
b.

Hence solve: h(x+1)=0h(x + 1) = 0h(x+1)=0

[2]

Inverse and Composite Functions Questions

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