Using xn+1=4xn2+3\displaystyle x_{n+1} = \frac{4}{x_n^2} + 3xn+1=xn24+3 with x0=3.2x_0 = 3.2x0=3.2
Find the values of x1x_1x1, x2 x_2\,x2 and x3x_3x3.
Explain the relationship between the values of x1x_1x1, x2 x_2\,x2 and x3 x_3\,x3 and the equation x3−3x2−4=0x^3 - 3x^2 - 4 = 0x3−3x2−4=0
