Recurring Decimals to Fractions

$k\,$ is an integer such that $\leq k \leq 9\,$

Prove that $0.k˙0˙=10k99\displaystyle 0.\dot{k}\dot{0} = \frac{10k}{99}$

[2]

$k\,$ is an integer such that $\leq k \leq 9\,$

Prove that $0.k˙0˙=10k99\displaystyle 0.\dot{k}\dot{0} = \frac{10k}{99}$

[2]

Recurring Decimals to Fractions Questions