b=(−24)\mathbf{b} = \begin{pmatrix} -2 \\ 4 \end{pmatrix}b=(−24) 3a+b=(10−5)3\mathbf{a} + \mathbf{b} = \begin{pmatrix} 10 \\ -5 \end{pmatrix}3a+b=(10−5)
Work out a\mathbf{a}a as a column vector.
75 exam-style questions on WJEC GCSE Maths Vectors. Each one has a worked solution and a mark scheme showing where the marks go.