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Factorising Harder Quadratics

Factorising Harder Quadratics

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Question 25

Solve 4x2−19x−5=04x^2 - 19x - 5 = 04x2−19x−5=0

Hence, solve 4(2x+1)2−19(2x+1)−5=04(2x+1)^2 - 19(2x+1) - 5 = 04(2x+1)2−19(2x+1)−5=0

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Factorising Harder Quadratics Questions

  1. GCSE
  2. /Maths
  3. /Factorising Harder Quadratics

223 exam-style questions on OCR GCSE Maths Factorising Harder Quadratics. Each one has a worked solution and a mark scheme showing where the marks go.

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