Find the value of (827)−23\displaystyle \left(\frac{8}{27}\right)^{-\frac{2}{3}}(278)−32
Hence, find the value of (827)−23−14\displaystyle \left(\frac{8}{27}\right)^{-\frac{2}{3}}-\frac{1}{4}(278)−32−41
352 exam-style questions on OCR GCSE Maths Fractional and Negative Indices. Each one has a worked solution and a mark scheme showing where the marks go.