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Perpendicular Lines and the equation of a tangent

Perpendicular Lines and the equation of a tangent

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Question 71

Here are the equations of 5 straight lines.

P:y=3x+4 P: y = 3x + 4 P:y=3x+4 Q:y=−3x+4 Q: y = -3x + 4 Q:y=−3x+4 R:y=x+4 R: y = x + 4 R:y=x+4 S:y=−13x+7 S: y = -\frac{1}{3}x + 7 S:y=−31​x+7 T:y=13x+2 T: y = \frac{1}{3}x + 2 T:y=31​x+2
a.

Write down the letter of the line that is parallel to y=x+8y = x + 8y=x+8

[1]
b.

Write down the letter of the line that is perpendicular to y=3x−1y = 3x - 1y=3x−1 Hence, write down the gradient of this line.

[2]
Markscheme

Perpendicular Lines and the equation of a tangent Questions

  1. GCSE
  2. /Maths
  3. /Perpendicular Lines and the equation of a tangent

130 exam-style questions on Eduqas GCSE Maths Perpendicular Lines and the equation of a tangent. Each one has a worked solution and a mark scheme showing where the marks go.

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