Show that 3x2−6x+6=3(x−1)2+33x^2 - 6x + 6 = 3(x - 1)^2 + 33x2−6x+6=3(x−1)2+3.
Hence, or otherwise, write down the coordinates of the turning point of the graph of y=3x2−6x+6y = 3x^2 - 6x + 6y=3x2−6x+6
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