Write (x−3)2−8(x - 3)^2 - 8(x−3)2−8 in the form x2+ax+bx^2 + ax + bx2+ax+b where a a\,a and b b\,b are integers.
Hence, or otherwise, write down the coordinates of the turning point of the graph of y=(x−3)2−8y = (x - 3)^2 - 8y=(x−3)2−8
250 exam-style questions on Eduqas GCSE Maths Completing the Square. Each one has a worked solution and a mark scheme showing where the marks go.