Simplify fully 3x+6x−4÷2x2+9x+10x2−4x\displaystyle \frac{3x+6}{x-4} \div \frac{2x^2+9x+10}{x^2-4x}x−43x+6÷x2−4x2x2+9x+10 Hence, solve 3x2x+5=3\displaystyle \frac{3x}{2x+5}=32x+53x=3
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