Simplify fully 2x−4x+4÷x2−7x+103x2+14x+8\displaystyle \frac{2x-4}{x+4} \div \frac{x^2-7x+10}{3x^2+14x+8}x+42x−4÷3x2+14x+8x2−7x+10
Hence solve 2x−4x+4÷x2−7x+103x2+14x+8=8\displaystyle \frac{2x-4}{x+4} \div \frac{x^2-7x+10}{3x^2+14x+8}=8x+42x−4÷3x2+14x+8x2−7x+10=8
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