Using xn+1=1xn2+1\displaystyle x_{n+1} = \frac{1}{x_n^2 + 1}xn+1=xn2+11 with x0=0x_0 = 0x0=0
Find the values of x1x_1x1, x2 x_2\,x2 and x3x_3x3.
124 exam-style questions on Eduqas GCSE Maths Iteration. Each one has a worked solution and a mark scheme showing where the marks go.