Given that x=2px = 2^px=2p and y=2qy = 2^qy=2q, verify that
2p+q=xy2^{p+q}=xy2p+q=xy
22p=x22^{2p}=x^222p=x2
2q−1=y2\displaystyle 2^{q-1}=\frac{y}{2}2q−1=2y
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