Rearranging Harder Formulae
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Revision notes for Edexcel GCSE Maths Rearranging Harder Formulae. Open the guide for explanations and worked examples. Written against the Edexcel GCSE Maths (1MA1) specification, so the content matches what's examinable rather than general Maths background.

Rearranging Harder Formulae

What you'll learn

  • How to make a chosen letter the subject of a formula.
  • How to undo brackets, powers and fractions in the right order.
  • How to handle formulae where the subject appears more than once.
  • How to spot common traps in Grade 7 rearranging questions.

1. Start with the subject

When you rearrange a formula, your aim is to get one chosen letter on its own.

All the other letters are treated like numbers. For example, if you are making xxx the subject, then aaa, bbb and ccc are just constants.

Definition

Subject of a formula

The subject of a formula is the letter that is on its own on one side of the equals sign. In A=πr2A = \pi r^2A=πr2, the subject is AAA.

The subject of a formula is the single letter isolated on one side of the equals sign.

Key Idea

The balance rule

Whatever you do to one side of the equation, you must do to the other side as well.

An equation stays balanced only when the same operation is applied to both sides.

Example

Make r the subject of w=r+kt

To make r the subject, undo the added kt by subtracting kt from both sides.

  1. Start with the formula.

    w=r+ktw = r + ktw=r+kt
  2. The term ktktkt is being added to rrr, so subtract ktktkt from both sides.

    w−kt=rw - kt = rw−kt=r
  3. Write the answer with rrr on the left.

    r=w−ktr = w - ktr=w−kt

2. Use inverse operations

An inverse operation is the operation that undoes another operation. Adding is undone by subtracting. Multiplying is undone by dividing. Squaring is undone by square rooting.

If the subject is inside several operations, undo them from the outside in.

Example

Make k the subject of w=r+kt

To isolate k, undo the outside addition first, then undo multiplication by t.

  1. Start with the formula.

    w=r+ktw = r + ktw=r+kt
  2. Subtract rrr from both sides to isolate the term containing kkk.

    w−r=ktw - r = ktw−r=kt
  3. Divide both sides by ttt.

    k=w−rtk = \frac{w - r}{t}k=tw−r​
Tip

Treat letters like numbers

If you are making kkk the subject, then rrr and ttt behave like fixed numbers. Do not be put off just because they are letters.

3. Rearranging with squares and roots

A square root undoes a square. If you have p2p^2p2, square rooting gives ppp.

Be careful: in pure algebra, square rooting can give a positive or negative answer.

Common Mistake

Square roots can have two signs

If the formula is about a length, speed or other quantity that cannot be negative, you usually take the positive square root. Without context, write ±\pm±.

Example

Make p the subject of q2=p2+5rs

First isolate p², then square root both sides to make p the subject.

  1. Start by isolating p2p^2p2. Subtract 5rs5rs5rs from both sides.

    q2−5rs=p2q^2 - 5rs = p^2q2−5rs=p2
  2. Square root both sides.

    p=±q2−5rsp = \pm\sqrt{q^2 - 5rs}p=±q2−5rs​

4. Fractions attached to terms

A coefficient is a number or expression multiplying a variable. In 12kt2\frac{1}{2}kt^221​kt2, the coefficient of kkk is 12t2\frac{1}{2}t^221​t2.

To remove a fraction like 12\frac{1}{2}21​, multiply by 2.

Example

Make k the subject of D=nt+21​kt2

  1. Subtract ntntnt from both sides.

    D−nt=12kt2D - nt = \frac{1}{2}kt^2D−nt=21​kt2
  2. Multiply both sides by 2.

    2(D−nt)=kt22(D - nt) = kt^22(D−nt)=kt2
  3. Divide both sides by t2t^2t2.

    k=2(D−nt)t2k = \frac{2(D - nt)}{t^2}k=t22(D−nt)​
Common Mistake

Forgetting the whole coefficient

In 12kt2\frac{1}{2}kt^221​kt2, the letter kkk is multiplied by both 12\frac{1}{2}21​ and t2t^2t2. You must undo both parts.

The whole coefficient attached to k is both 1/2 and t², so both must be undone.

5. When the subject appears more than once

Sometimes the letter you want appears in two places. You cannot make it the subject until you have collected all those terms together.

To factorise means to take out a common factor. For example, 4y+cy−dy4y + cy - dy4y+cy−dy becomes y(4+c−d)y(4 + c - d)y(4+c−d).

Factorising collects repeated y terms by taking y outside a bracket.

Example

Make y the subject of y(4+c)=d(y+5)

  1. Expand the brackets.

    4y+cy=dy+5d4y + cy = dy + 5d4y+cy=dy+5d
  2. Move all the yyy terms to one side.

    4y+cy−dy=5d4y + cy - dy = 5d4y+cy−dy=5d
  3. Factorise by taking out yyy.

    y(4+c−d)=5dy(4 + c - d) = 5dy(4+c−d)=5d
  4. Divide by 4+c−d4 + c - d4+c−d.

    y=5d4+c−dy = \frac{5d}{4 + c - d}y=4+c−d5d​
Common Mistake

Cancelling too early

Do not cancel the subject letter from both sides if it appears in separate added or subtracted terms. Collect and factorise first.

6. Algebraic fractions

A denominator is the bottom part of a fraction. In x+1x−3\frac{x + 1}{x - 3}x−3x+1​, the denominator is x−3x - 3x−3.

To remove an algebraic fraction, multiply both sides by the denominator. This is often called clearing the fraction.

Example

Make y the subject of a=3y−25+3cy​

  1. Multiply both sides by 3y−23y - 23y−2.

    a(3y−2)=5+3cya(3y - 2) = 5 + 3cya(3y−2)=5+3cy
  2. Expand the left-hand side.

    3ay−2a=5+3cy3ay - 2a = 5 + 3cy3ay−2a=5+3cy
  3. Collect the yyy terms on one side.

    3ay−3cy=5+2a3ay - 3cy = 5 + 2a3ay−3cy=5+2a
  4. Factorise and divide.

    y(3a−3c)=5+2ay=5+2a3a−3c\begin{aligned} y(3a - 3c) &= 5 + 2a \\ y &= \frac{5 + 2a}{3a - 3c} \end{aligned}y(3a−3c)y​=5+2a=3a−3c5+2a​​
Tip

Check denominators

Original denominators cannot be zero. In the example above, 3y−2≠03y - 2 \neq 03y−2=0, so any final answer must respect that restriction.

7. Reciprocal formulae

The reciprocal of a number or expression is 1 divided by it. For example, the reciprocal of qqq is 1q\frac{1}{q}q1​.

For reciprocal formulae, a reliable method is to multiply every term by all the denominators.

Multiplying every term by pqr clears the reciprocal denominators p, q and r.

Example

Make q the subject of p1​=q1​+r1​

  1. Start with the formula.

    1p=1q+1r\frac{1}{p} = \frac{1}{q} + \frac{1}{r}p1​=q1​+r1​
  2. Multiply every term by pqrpqrpqr.

    qr=pr+pqqr = pr + pqqr=pr+pq
  3. Collect the terms containing qqq.

    qr−pq=prqr - pq = prqr−pq=pr
  4. Factorise and divide.

    q(r−p)=prq=prr−p\begin{aligned} q(r - p) &= pr \\ q &= \frac{pr}{r - p} \end{aligned}q(r−p)q​=pr=r−ppr​​
Exam technique

In the exam

  1. Circle the letter you are making the subject before you start.

  2. Clear brackets and fractions early if they are blocking the subject.

  3. If the subject appears more than once, collect those terms, factorise, then divide.

  4. Check your answer by seeing whether the subject is completely alone on one side.

Self review

Check yourself

  • Can you explain why x(a+b)x(a + b)x(a+b) cannot usually be changed into xa+bxa + bxa+b?

  • If xxx appears on both sides of a formula, what three actions should you try?

  • When rearranging a formula with v2v^2v2, when might you need a ±\pm± sign?

Recap questions

Test yourself with 5 quick questions on this guide. Answer them all correctly to complete it.

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