Revision notes for Edexcel GCSE Maths Histograms. Open the guide for explanations and worked examples. Written against the Edexcel GCSE Maths (1MA1) specification, so the content matches what's examinable rather than general Maths background.
Revision notes for Edexcel GCSE Maths Histograms. Open the guide for explanations and worked examples. Written against the Edexcel GCSE Maths (1MA1) specification, so the content matches what's examinable rather than general Maths background.
Histograms are used when numerical data has been grouped into ranges. This is common for measurement data, such as time, length or mass, where values can be decimals.
The class interval 0≤t<50 \le t < 50≤t<5 means values from 0 up to, but not including, 5. A value of exactly 5 would go into the next class.
Key histogram words
A histogram is a graph for grouped continuous data where bar area represents frequency.
Continuous data is measurement data that can take any value in a range, such as 3.7 hours.
The frequency is how many values are in a group.
A class interval is one group, such as 10≤t<1510 \le t < 1510≤t<15.
The class width is the length of the interval: upper boundary minus lower boundary.
Finding class widths
A survey records time ttt in hours using the groups 0≤t<30 \le t < 30≤t<3, 3≤t<83 \le t < 83≤t<8, 8≤t<148 \le t < 148≤t<14 and 14≤t<2414 \le t < 2414≤t<24. Find the class widths.

The class width is found by subtracting the lower boundary from the upper boundary.
Calculate each width:
0≤t<3:3−0=33≤t<8:8−3=58≤t<14:14−8=614≤t<24:24−14=10\begin{aligned} 0 \le t < 3 &: 3-0=3\\ 3 \le t < 8 &: 8-3=5\\ 8 \le t < 14 &: 14-8=6\\ 14 \le t < 24 &: 24-14=10 \end{aligned}0≤t<33≤t<88≤t<1414≤t<24:3−0=3:8−3=5:14−8=6:24−14=10The class widths are 3 hours, 5 hours, 6 hours and 10 hours.
Width matters
In a histogram, the horizontal width of each bar is part of the calculation, not just decoration.
In a bar chart, the height usually shows the frequency. In a histogram, that is not usually true.
The vertical axis is normally labelled frequency density, often shortened to f.d. This is the height of the bar.
Frequency density
Frequency density is frequency per unit of class width.
frequency density=frequencyclass width\text{frequency density}=\frac{\text{frequency}}{\text{class width}}frequency density=class widthfrequencyFinding the height of a histogram bar
In one class interval, 2≤t<82 \le t < 82≤t<8, the frequency is 18. Find the frequency density.

Find the class width. From 2 to 8 is a width of 6.
Divide the frequency by the class width:
frequency density=186=3\text{frequency density}=\frac{18}{6}=3frequency density=618=3The histogram bar should have height 3 on the frequency density axis.
Using frequency as the height
Do not draw a bar of height 18 just because the frequency is 18. First divide by the class width to get the frequency density.
A histogram bar is a rectangle. The area of a rectangle is its width times its height.
In a histogram:
frequency=class width×frequency density\text{frequency}=\text{class width}\times\text{frequency density}frequency=class width×frequency densityArea gives frequency
In histograms, frequency is shown by the area of the bar, not just by the height.
Finding frequency from a bar
On a histogram of waiting times, the bar for 8≤t<168 \le t < 168≤t<16 has frequency density 1.75. Find the frequency.

Find the class width. From 8 to 16 is a width of 8.
Multiply the width by the frequency density:
frequency=8×1.75=14\text{frequency}=8 \times 1.75=14frequency=8×1.75=14The frequency is 14.
Many exam questions give you a partially completed histogram or table. Use whichever formula fits the missing value:
Completing a histogram-style table
A histogram records time ttt in hours. The information is:
0≤t<40 \le t < 40≤t<4: frequency 10
4≤t<94 \le t < 94≤t<9: frequency density 1.4
9≤t<159 \le t < 159≤t<15: frequency density 1.5
15≤t<2515 \le t < 2515≤t<25: frequency 12
Complete the missing values and describe how to draw the bars.

Find all the class widths:
0≤t<4:44≤t<9:59≤t<15:615≤t<25:10\begin{aligned} 0 \le t < 4 &: 4\\ 4 \le t < 9 &: 5\\ 9 \le t < 15 &: 6\\ 15 \le t < 25 &: 10 \end{aligned}0≤t<44≤t<99≤t<1515≤t<25:4:5:6:10For rows where the frequency is known, divide by the width:
f.d. for 0≤t<4=104=2.5f.d. for 15≤t<25=1210=1.2\begin{aligned} \text{f.d. for }0 \le t < 4 &= \frac{10}{4}=2.5\\ \text{f.d. for }15 \le t < 25 &= \frac{12}{10}=1.2 \end{aligned}f.d. for 0≤t<4f.d. for 15≤t<25=410=2.5=1012=1.2For rows where the frequency density is known, multiply by the width:
frequency for 4≤t<9=5×1.4=7frequency for 9≤t<15=6×1.5=9\begin{aligned} \text{frequency for }4 \le t < 9 &= 5 \times 1.4=7\\ \text{frequency for }9 \le t < 15 &= 6 \times 1.5=9 \end{aligned}frequency for 4≤t<9frequency for 9≤t<15=5×1.4=7=6×1.5=9The completed values are:
0≤t<40 \le t < 40≤t<4: frequency 10, frequency density 2.5.
4≤t<94 \le t < 94≤t<9: frequency 7, frequency density 1.4.
9≤t<159 \le t < 159≤t<15: frequency 9, frequency density 1.5.
15≤t<2515 \le t < 2515≤t<25: frequency 12, frequency density 1.2.
To draw the histogram, draw touching rectangles over the correct intervals, with heights 2.5, 1.4, 1.5 and 1.2.
Drawing equal-width bars
Do not draw every bar the same width. A class from 15 to 25 must be wider than a class from 4 to 9.

Sometimes you need only part of a class interval, such as estimating how many values are between 12 and 18 when the bar covers 10 to 20.
Estimate
An estimate is an approximate answer. When using part of a histogram bar, you assume the data is evenly spread within that class interval.
Estimating from part of a histogram bar
A bar covers 10≤t<2010 \le t < 2010≤t<20 and has frequency density 2.5. Estimate the frequency for 12≤t<1812 \le t < 1812≤t<18.

The smaller interval from 12 to 18 has width 6.
This interval is inside the same bar, so use the same frequency density, 2.5.
Multiply width by frequency density:
frequency=6×2.5=15\text{frequency}=6 \times 2.5=15frequency=6×2.5=15The estimated frequency is 15.
Only an estimate
Partial-bar answers assume the data is evenly spread inside the class. Real data may not be, so these answers are estimates.
In the exam
Read the vertical axis carefully: if it says frequency density, height is not frequency.
Write the class width beside every interval before calculating.
Use area: frequency=width×frequency density\text{frequency}=\text{width}\times\text{frequency density}frequency=width×frequency density.
When drawing, make bars touch and give each bar the correct horizontal width.
Check yourself
Can you explain why a histogram bar with height 2 and width 10 has frequency 20?
If a class interval is 7≤t<157 \le t < 157≤t<15, what is its class width?
When would you divide frequency by class width, and when would you multiply?
Test yourself with 5 quick questions on this guide. Answer them all correctly to complete it.