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Question 5

Using xn+1=2+7xn\displaystyle x_{n+1} = 2 + \frac{7}{x_n}xn+1​=2+xn​7​ with x0=4x_0 = 4x0​=4

Find the values of x1x_1x1​, x2 x_2\,x2​ and x3x_3x3​.

[3]
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Iteration Questions

  1. GCSE
  2. /Maths
  3. /Iteration

40 exam-style questions on Edexcel GCSE Maths Iteration. Each one has a worked solution and a mark scheme showing where the marks go.

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