Using xn+1=3+9xn2\displaystyle x_{n+1} = 3 + \frac{9}{x_n^2}xn+1=3+xn29 with x0=3x_0 = 3x0=3
Find the values of x1x_1x1, x2 x_2\,x2 and x3x_3x3.
40 exam-style questions on Edexcel GCSE Maths Iteration. Each one has a worked solution and a mark scheme showing where the marks go.