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Fractional and Negative Indices

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Question 34

Find the value of (1625)−12\displaystyle \left(\frac{16}{25}\right)^{-\frac{1}{2}}(2516​)−21​

[2]
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Fractional and Negative Indices Questions

  1. GCSE
  2. /Maths
  3. /Fractional and Negative Indices

352 exam-style questions on Edexcel GCSE Maths Fractional and Negative Indices. Each one has a worked solution and a mark scheme showing where the marks go.

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