- How to complete a table of values for a quadratic formula.
- How to plot points and draw a smooth quadratic curve.
- How to read roots and turning points from a graph.
- How to use a graph to estimate solutions to equations.
A coordinate tells you a point’s position on a grid. It is written as (x,y)(x,y)(x,y), where the first number is across and the second number is up or down.
To draw a graph, you choose values of xxx, substitute them into the formula, and calculate the matching values of yyy.
Substituting into a quadratic formula
For y=x2−2x−1y=x^2-2x-1y=x2−2x−1, find yyy when x=−1x=-1x=−1, x=0x=0x=0, and x=3x=3x=3.
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Substitute x=−1x=-1x=−1:
y=(−1)2−2(−1)−1=1+2−1=2y=(-1)^2-2(-1)-1=1+2-1=2y=(−1)2−2(−1)−1=1+2−1=2
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Substitute x=0x=0x=0:
y=02−2(0)−1=−1y=0^2-2(0)-1=-1y=02−2(0)−1=−1
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Substitute x=3x=3x=3:
y=32−2(3)−1=9−6−1=2y=3^2-2(3)-1=9-6-1=2y=32−2(3)−1=9−6−1=2
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So the points you would plot are (−1,2)(-1,2)(−1,2), (0,−1)(0,-1)(0,−1), and (3,2)(3,2)(3,2).
Negative x-values
When you square a negative number, the answer is positive: (−3)2=9(-3)^2=9(−3)2=9, not -9. Use brackets when substituting negative values.
Quadratic graph
A quadratic graph is the graph of a formula with an x2x^2x2 term, such as y=x2+x−6y=x^2+x-6y=x2+x−6 or y=7x−x2y=7x-x^2y=7x−x2. Its shape is a smooth curve called a parabola.
A parabola can open upwards or downwards.

- If the x2x^2x2 term is positive, the graph opens upwards like a smile.
- If the x2x^2x2 term is negative, the graph opens downwards like a frown.
The overall shape
Quadratic graphs are not straight lines. They should be drawn as one smooth curve through the plotted points.
Deciding the shape
Look at y=5x−x2y=5x-x^2y=5x−x2. Decide whether the graph opens upwards or downwards.

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Rewrite the formula mentally as y=−x2+5xy=-x^2+5xy=−x2+5x.
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The coefficient of x2x^2x2 is negative.
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So the graph opens downwards.
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This means it will have a highest point rather than a lowest point.
A table of values lists chosen xxx-values and their matching yyy-values. You use it to create points for your graph.
Completing a table of values
Complete the table for y=x2−x−4y=x^2-x-4y=x2−x−4, for x=−2x=-2x=−2 to x=4x=4x=4.

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Substitute x=−2x=-2x=−2:
y=(−2)2−(−2)−4=4+2−4=2y=(-2)^2-(-2)-4=4+2-4=2y=(−2)2−(−2)−4=4+2−4=2
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Substitute x=−1x=-1x=−1:
y=(−1)2−(−1)−4=1+1−4=−2y=(-1)^2-(-1)-4=1+1-4=-2y=(−1)2−(−1)−4=1+1−4=−2
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Continue in the same way for each xxx-value.
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The completed table is:
Quick check
Quadratic tables often have a pattern: the yyy-values decrease, reach a lowest or highest area, then increase again. If one value looks wildly out of place, recalculate it.
Once the table is complete, turn each pair into a coordinate. For example, if x=−2x=-2x=−2 and y=2y=2y=2, plot (−2,2)(-2,2)(−2,2).
Use small crosses or dots, then draw a smooth curve through them.
Drawing the graph from a table
Use these values for y=x2−x−4y=x^2-x-4y=x2−x−4:

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Turn the table into points: (−2,2)(-2,2)(−2,2), (−1,−2)(-1,-2)(−1,−2), (0,−4)(0,-4)(0,−4), (1,−4)(1,-4)(1,−4), (2,−2)(2,-2)(2,−2), (3,2)(3,2)(3,2), and (4,8)(4,8)(4,8).
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Plot each point carefully on the grid.
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Check that the points make a curved pattern, not a straight-line pattern.
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Draw one smooth U-shaped curve through the points.
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The lowest part of the graph is between x=0x=0x=0 and x=1x=1x=1, so the turning point is about (0.5,−4.3)(0.5,-4.3)(0.5,−4.3).
Joining with straight lines
Do not join quadratic points using a ruler. A quadratic graph is a smooth curve, so the line should bend gradually through the points.
Roots and turning point
The roots of a quadratic are the xxx-values where the graph crosses the xxx-axis. The turning point is the lowest point or highest point of the parabola.

Roots happen where y=0y=0y=0, because every point on the xxx-axis has a yyy-coordinate of 0.
Reading from a quadratic graph
A graph of y=x2−4x+3y=x^2-4x+3y=x2−4x+3 has its lowest point at (2,−1)(2,-1)(2,−1). It crosses the xxx-axis at x=1x=1x=1 and x=3x=3x=3. Find the turning point and the roots of x2−4x+3=0x^2-4x+3=0x2−4x+3=0.

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The turning point is the lowest point of the graph.
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So the turning point is (2,−1)(2,-1)(2,−1).
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The roots are where the graph crosses the xxx-axis.
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The graph crosses at x=1x=1x=1 and x=3x=3x=3.
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So the roots are x=1x=1x=1 and x=3x=3x=3.
Sometimes the equation is not equal to 0. For example, to solve x2−x−4=−2x^2-x-4=-2x2−x−4=−2, you look for where the graph has y=−2y=-2y=−2.
That means you use a horizontal line, which goes straight across the grid.
Solving an equation from a graph
Use the graph of y=x2−x−4y=x^2-x-4y=x2−x−4 to solve x2−x−4=−2x^2-x-4=-2x2−x−4=−2.

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Notice that x2−x−4x^2-x-4x2−x−4 is the expression used for yyy.
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The equation asks where y=−2y=-2y=−2.
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On the graph, draw or imagine the horizontal line y=−2y=-2y=−2.
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Read the xxx-values where this horizontal line meets the curve.
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From the table and graph, this happens at x=−1x=-1x=−1 and x=2x=2x=2.
Sometimes you need to rearrange the equation first.
Rearranging before using the graph
Use the graph of y=x2−3x−4y=x^2-3x-4y=x2−3x−4 to solve x2=3x+4x^2=3x+4x2=3x+4.

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Rearrange the equation so one side is 0:
x2−3x−4=0x^2-3x-4=0x2−3x−4=0
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This matches the graph y=x2−3x−4y=x^2-3x-4y=x2−3x−4.
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So you need the roots of the graph.
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Read the xxx-axis crossings.
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If the graph crosses at x=−1x=-1x=−1 and x=4x=4x=4, the solutions are x=−1x=-1x=−1 and x=4x=4x=4.
Forgetting to rearrange
If the equation is x2=3x+4x^2=3x+4x2=3x+4, do not look for where y=3x+4y=3x+4y=3x+4 on a graph of y=x2−3x−4y=x^2-3x-4y=x2−3x−4. Rearrange first, then use the roots.
In the exam
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Complete the table carefully, especially negative xxx-values and any minus sign in front of x2x^2x2.
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Plot points accurately, then draw a smooth curve rather than straight line segments.
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Roots are xxx-axis crossings; equations like x2−x−4=−2x^2-x-4=-2x2−x−4=−2 use the horizontal line y=−2y=-2y=−2.
Check yourself
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If x=−3x=-3x=−3, what is x2x^2x2?
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Where on a quadratic graph do you read the roots?
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How would you use a graph of y=x2−2x−1y=x^2-2x-1y=x2−2x−1 to solve x2−2x−1=3x^2-2x-1=3x2−2x−1=3?