- How to read coordinates from a graph accurately.
- Why the point where two lines meet solves both equations.
- How to draw straight-line graphs from equations.
- How to use the intersection point to solve simultaneous equations.
A graph has two axes:
- the horizontal axis is the x-axis
- the vertical axis is the y-axis
A point is written as a coordinate pair.
Coordinate pair
A coordinate pair (x,y)(x, y)(x,y) tells you the position of a point. The first number is the x-coordinate, and the second number is the y-coordinate.
Reading a coordinate
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Start at the origin, which is the centre point where the axes cross.
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Move 4 squares to the right, so the x-coordinate is 4.
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Move 1 square up, so the y-coordinate is 1.
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The coordinate of the point is (4,1)(4, 1)(4,1).

Writing coordinates backwards
Coordinates are always written x first, then y. So (4,1)(4, 1)(4,1) is not the same as (1,4)(1, 4)(1,4).
Simultaneous equations are equations that are solved at the same time.
Simultaneous equations
A pair of simultaneous equations has one solution if there is one pair of values for xxx and yyy that makes both equations true.
On a graph, each straight line shows all the points that satisfy one equation. The point where two lines meet satisfies both equations.

The key idea
The solution to two simultaneous equations is the coordinate of the point where the two graphs intersect.
Checking a shared solution
For the equations y=2x+1y = 2x + 1y=2x+1 and x+y=4x + y = 4x+y=4, check whether (1,3)(1, 3)(1,3) is a solution.
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Substitute x=1x = 1x=1 and y=3y = 3y=3 into the first equation.
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This gives 3=2×1+13 = 2 \times 1 + 13=2×1+1, which is true.
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Substitute x=1x = 1x=1 and y=3y = 3y=3 into the second equation.
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This gives 1+3=41 + 3 = 41+3=4, which is true.
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So (1,3)(1, 3)(1,3) is a solution to both equations.

Sometimes the lines are already drawn for you. Your job is to find where they cross.
To solve graphically:
- Find the point where the two lines intersect.
- Read the x-coordinate.
- Read the y-coordinate.
- Write the solution as x=...x = \text{...}x=... and y=...y = \text{...}y=....
Using two drawn lines
The graphs of y=x+1y = x + 1y=x+1 and 2x+y=72x + y = 72x+y=7 are drawn on the same grid. They cross at (2,3)(2, 3)(2,3).

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Find the point where the two straight lines meet.
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Read across or down to the x-axis. The x-coordinate is 2.
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Read across to the y-axis. The y-coordinate is 3.
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Therefore the solution is x=2x = 2x=2 and y=3y = 3y=3.
A straight-line graph is made by plotting points that satisfy an equation, then joining them with a ruler.
For equations like y=2x−1y = 2x - 1y=2x−1, you can choose some x-values, calculate the matching y-values, then plot the points.
Drawing a line from y = 2x - 1
Draw the graph of y=2x−1y = 2x - 1y=2x−1.

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Choose some simple x-values, such as 0, 1 and 2.
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Calculate the y-values.
x=0⇒y=−1x=1⇒y=1x=2⇒y=3\begin{aligned}
x = 0 &\Rightarrow y = -1 \\
x = 1 &\Rightarrow y = 1 \\
x = 2 &\Rightarrow y = 3
\end{aligned}x=0x=1x=2⇒y=−1⇒y=1⇒y=3
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Plot the points (0,−1)(0, -1)(0,−1), (1,1)(1, 1)(1,1) and (2,3)(2, 3)(2,3).
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Join the points with a straight line using a ruler.
Use at least two points
Two points are enough to draw a straight line, but plotting three points helps you spot mistakes.
Some equations are not already written as y=...y = \text{...}y=.... You may need to rearrange them first.
To make yyy the subject means to get yyy on its own on one side of the equation.
Rearranging before drawing
Draw the graph of 2y−x=62y - x = 62y−x=6.

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Add xxx to both sides to get 2y=x+62y = x + 62y=x+6.
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Divide both sides by 2 to get y=12x+3y = \frac{1}{2}x + 3y=21x+3.
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Choose easy x-values. If x=0x = 0x=0, then y=3y = 3y=3.
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If x=2x = 2x=2, then y=4y = 4y=4.
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If x=4x = 4x=4, then y=5y = 5y=5.
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Plot (0,3)(0, 3)(0,3), (2,4)(2, 4)(2,4) and (4,5)(4, 5)(4,5), then join them with a straight line.
Choose friendly values
If the equation has a fraction like 12x\frac{1}{2}x21x, choosing even x-values often gives whole-number y-values.
If you are given two equations and no graph, draw both lines on the same set of axes. The answer is where they meet.
Solving graphically
Solve the simultaneous equations y=−x+4y = -x + 4y=−x+4 and 2y−x=22y - x = 22y−x=2 using graphs.

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Draw the first line, y=−x+4y = -x + 4y=−x+4. Two easy points are (0,4)(0, 4)(0,4) and (4,0)(4, 0)(4,0).
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Rearrange the second equation: 2y−x=22y - x = 22y−x=2 becomes y=12x+1y = \frac{1}{2}x + 1y=21x+1.
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Draw the second line using points such as (0,1)(0, 1)(0,1), (2,2)(2, 2)(2,2) and (4,3)(4, 3)(4,3).
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Look carefully at the point where the two lines intersect.
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The lines meet at (2,2)(2, 2)(2,2).
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Therefore the solution is x=2x = 2x=2 and y=2y = 2y=2.
Sometimes the intersection is to the left of the y-axis or below the x-axis. That means one or both coordinates are negative.
Reading a negative intersection
The graphs of y=x−1y = x - 1y=x−1 and y=−2x−4y = -2x - 4y=−2x−4 are drawn on the same grid.

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Find the point where the lines intersect.
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The crossing is one square left of the y-axis, so x=−1x = -1x=−1.
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The crossing is two squares below the x-axis, so y=−2y = -2y=−2.
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The solution is x=−1x = -1x=−1 and y=−2y = -2y=−2.
Parallel lines
If two straight lines are parallel, they never meet. That means there is no solution to the simultaneous equations.
Graphical solutions depend on how carefully you draw and read the graph. If the intersection is exactly on a grid point, give exact coordinates. If it is between grid lines, give the best estimate you can.
In the exam
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Use a sharp pencil and a ruler when drawing straight lines.
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Label each line or make it clear which equation it represents.
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Read the intersection carefully: x-coordinate first, then y-coordinate.
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If possible, substitute your answer back into the equations to check it makes sense.
Check yourself
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Why does the intersection point solve both equations?
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How do you know which number is the x-coordinate?
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What should you do if the equation is not written in the form y=...y = \text{...}y=...?