- How to continue a sequence by spotting the rule.
- How to use an nth-term formula to find terms.
- How to decide whether a number is in a sequence.
- How to find the nth term of an arithmetic sequence.
A sequence is a list of numbers or patterns in order. The order matters.
Sequence words
-
A sequence is an ordered list, such as 5, 8, 12, 17.
-
A term is one number in the sequence.
-
The position tells you where the term is: first, second, third, and so on.
-
A term-to-term rule tells you how to get from one term to the next.
To continue a sequence, look at the gaps between terms.
Continuing a sequence from the gaps
The first terms are 5, 8, 12, 17. Find the next two terms.

-
Work out the gaps: from 5 to 8 is +3, from 8 to 12 is +4, and from 12 to 17 is +5.
-
The gaps are increasing by 1 each time, so the next gaps are +6 and +7.
-
Add 6 to 17 to get 23.
-
Add 7 to 23 to get 30.
-
The next two terms are 23 and 30.
Assuming the gap is always the same
Do not just use the first gap. Check all the gaps you are given, because some sequences have changing gaps.
If a sequence starts at a number and keeps adding the same amount, you can check whether another number appears by looking at the difference from the first term.
Is a number in an add-on sequence?
The first term is 4. The rule is add 6. Is 83 a term?

-
The sequence starts 4, 10, 16, 22, and keeps adding 6.
-
Find the difference from the first term to 83: 83 − 4 = 79.
-
Since 79 is not a multiple of 6, you cannot reach 83 by adding 6s.
-
So 83 is not a term in the sequence.
Some term-to-term rules tell you exactly what to do each time, such as “multiply by 2 then subtract 1”. Follow the rule carefully, one term at a time.
Using a given term-to-term rule
A sequence starts with 3. The rule is: multiply the previous term by 2, then subtract 1. Find the 5th term.

-
Start with the first term: 3.
-
Double 3 and subtract 1 to get the second term: 5.
-
Double 5 and subtract 1 to get the third term: 9.
-
Double 9 and subtract 1 to get the fourth term: 17.
-
Double 17 and subtract 1 to get the fifth term: 33.
A Fibonacci-type sequence makes each new term by adding the two previous terms.
Continuing a Fibonacci-type sequence
The sequence begins 3, 4, 7, 11, 18. Find the next two terms.

-
Add the last two terms: 11 + 18 = 29.
-
The next term is 29.
-
Add the new last two terms: 18 + 29 = 47.
-
The next two terms are 29 and 47.
The nth term is a formula that tells you the term in position nnn.
Nth term
The letter nnn stands for the position number. So n=1n=1n=1 means the first term, n=2n=2n=2 means the second term, and so on.

To use an nth-term formula, substitute the position number into the formula.
Using a linear nth term
The nth term of a sequence is 5n+25n + 25n+2.

Find the first two terms, and decide whether 37 is a term.
-
For the first term, use n=1n=1n=1: 5(1)+2=75(1)+2=75(1)+2=7.
-
For the second term, use n=2n=2n=2: 5(2)+2=125(2)+2=125(2)+2=12.
-
The first two terms are 7 and 12.
-
To check whether 37 is a term, solve 5n+2=375n + 2 = 375n+2=37:
5n+2=375n=35n=7\begin{aligned}
5n + 2 &= 37 \\
5n &= 35 \\
n &= 7
\end{aligned}5n+25nn=37=35=7
-
Since 7 is a positive whole-number position, 37 is a term.
Starting with n = 0
In GCSE sequence questions, the first term is normally when n=1n=1n=1, not when n=0n=0n=0, unless the question says otherwise.
If the formula contains n2n^2n2, square the position number first.
Using a square nth term
The nth term is n2+5n^2 + 5n2+5.
Find the first three terms, and decide whether 54 is a term.
-
Use n=1n=1n=1: 12+5=61^2+5=612+5=6.
-
Use n=2n=2n=2: 22+5=92^2+5=922+5=9.
-
Use n=3n=3n=3: 32+5=143^2+5=1432+5=14.
-
To check 54, solve n2+5=54n^2 + 5 = 54n2+5=54:
n2+5=54n2=49n=7\begin{aligned}
n^2 + 5 &= 54 \\
n^2 &= 49 \\
n &= 7
\end{aligned}n2+5n2n=54=49=7
-
Since 7 is a positive whole-number position, 54 is a term.
Arithmetic sequence
An arithmetic sequence has the same difference between consecutive terms. Consecutive terms are terms next to each other. The fixed difference is called the common difference.
For an arithmetic sequence, the nth term has the form dn+cdn + cdn+c.
- ddd is the common difference.
- ccc is the adjustment needed to match the actual sequence.
The main nth-term idea
The number in front of nnn comes from the common difference, not from the first term.
Finding an increasing nth term
Find the nth term of 8, 13, 18, 23, 28.

-
The common difference is 5, because each term increases by 5.
-
Start with 5n5n5n. Its first few values are 5, 10, 15, 20, 25.
-
Compare with the actual sequence: 8, 13, 18, 23, 28.
-
Each actual term is 3 bigger than the matching 5n5n5n value.
-
So the nth term is 5n+35n + 35n+3.
If the sequence goes down, the common difference is negative.
Finding a decreasing nth term
Find the nth term of 26, 22, 18, 14, 10.
-
The sequence goes down by 4 each time, so the common difference is negative 4.
-
Start with −4n-4n−4n. Its first few values are negative 4, negative 8, negative 12.
-
To get from negative 4 to 26, add 30.
-
So the nth term is −4n+30-4n + 30−4n+30.
-
Check: when n=1n=1n=1, −4n+30=26-4n+30=26−4n+30=26.
Quick check
After finding an nth term, test it with n=1n=1n=1 and n=2n=2n=2. If it does not give the first two terms, fix it before moving on.
Pattern questions work like number sequences. The pattern number is the position number.
Count carefully, then look for what changes each time.
Counters in a growing pattern
A counter pattern has totals 6, 10, 14 for patterns 1, 2 and 3. Find a rule and work out pattern 8.

-
The totals increase by 4 each time, so this is an arithmetic sequence.
-
Start with 4n4n4n. The first value of 4n4n4n is 4.
-
Pattern 1 actually has 6 counters, which is 2 more than 4.
-
So the rule is 4n+24n + 24n+2.
-
For pattern 8, use n=8n=8n=8: 4(8)+2=344(8)+2=344(8)+2=34.
-
Pattern 8 has 34 counters.
In the exam
-
Write down the gaps between terms before deciding on a rule.
-
For an nth-term formula, substitute n=1n=1n=1, n=2n=2n=2, or the position the question asks for.
-
If checking whether a number is a term, solve for nnn. It must be a positive whole number.
Check yourself
-
Can you explain the difference between a term-to-term rule and an nth-term rule?
-
If a sequence goes down by 3 each time, what sign should the number in front of nnn have?
-
How can you check that your nth-term expression is correct?