Revision notes for Edexcel GCSE Maths Surface Area. Open the guide for explanations and worked examples. Written against the Edexcel GCSE Maths (1MA1) specification, so the content matches what's examinable rather than general Maths background.
Revision notes for Edexcel GCSE Maths Surface Area. Open the guide for explanations and worked examples. Written against the Edexcel GCSE Maths (1MA1) specification, so the content matches what's examinable rather than general Maths background.
A face is an outside surface of a 3D shape. Some faces are flat, like rectangles. Some are curved, like the side of a cylinder.
Surface area
Surface area is the total area of all the outside faces of a 3D shape. It is measured in square units, such as cm² or m².
For Grade 4 surface area, the main flat shapes are:
The perpendicular height is measured at 90° to the base, not along a slanted side.
Area of a trapezium face
A trapezium face has parallel sides 12 cm and 6 cm, with perpendicular height 5 cm.

Identify the values: a=12a=12a=12, b=6b=6b=6 and h=5h=5h=5.
Substitute into the trapezium formula:
A=12(12+6)×5A=\frac{1}{2}(12+6)\times 5A=21(12+6)×5Work it out:
A=12×18×5=45A=\frac{1}{2}\times 18\times 5=45A=21×18×5=45The area of the trapezium face is 45 cm².
A cuboid is a box shape with six rectangular faces. Opposite faces are the same size.
For a cuboid, there are three different rectangle areas:
Then each one is doubled.
Cuboid shortcut
For a cuboid, find the three different face areas, double each one, then add them.
Total surface area of a cuboid
A cuboid has length 9 cm, width 4 cm and height 3 cm. Find its total surface area.

Find the three different rectangular face areas:
9×4=36,9×3=27,4×3=129\times 4=36,\quad 9\times 3=27,\quad 4\times 3=129×4=36,9×3=27,4×3=12Double each area because there are matching opposite faces:
2×36+2×27+2×12=1502\times 36+2\times 27+2\times 12=1502×36+2×27+2×12=150The total surface area is 150 cm².
Only counting three faces
A cuboid has six faces, not three. Finding three different areas is useful, but you must double them.
Prism and cross-section
A prism is a 3D shape with the same shape all the way through. The cross-section is the repeated end shape.
For any prism:
total surface area=2×cross-section area+perimeter×length\text{total surface area}=2\times \text{cross-section area}+\text{perimeter}\times \text{length}total surface area=2×cross-section area+perimeter×lengthThe perimeter is the distance all the way around the cross-section.
A triangular prism has two triangular ends and three rectangular side faces.
Surface area of a triangular prism
A triangular prism has a right-angled triangular cross-section with sides 9 cm, 12 cm and 15 cm. The prism is 7 cm long.

Find the area of one triangular end:
12×9×12=54\frac{1}{2}\times 9\times 12=5421×9×12=54There are two triangular ends:
2×54=1082\times 54=1082×54=108Find the perimeter of the triangle:
9+12+15=369+12+15=369+12+15=36Find the total area of the rectangular side faces:
36×7=25236\times 7=25236×7=252Add the end faces and side faces:
108+252=360108+252=360108+252=360The total surface area is 360 cm².
A trapezium prism works in the same way, but the end face is a trapezium.
Surface area of a trapezium prism
A prism has a trapezium cross-section. The parallel sides are 12 cm and 6 cm, the perpendicular height is 4 cm, and the other two sides are both 5 cm. The prism is 8 cm long.

Find the area of one trapezium end:
12(12+6)×4=36\frac{1}{2}(12+6)\times 4=3621(12+6)×4=36There are two trapezium ends:
2×36=722\times 36=722×36=72Find the perimeter of the trapezium:
12+6+5+5=2812+6+5+5=2812+6+5+5=28Find the area of the rectangular side faces:
28×8=22428\times 8=22428×8=224Add everything:
72+224=29672+224=29672+224=296The total surface area is 296 cm².
A composite shape is made from two or more simpler shapes, or from one shape with a part removed.
For an L-shaped prism, you can still use:
total surface area=2×end area+perimeter×length\text{total surface area}=2\times \text{end area}+\text{perimeter}\times \text{length}total surface area=2×end area+perimeter×lengthThe tricky part is finding the area and perimeter of the L-shaped end.
Surface area of an L-shaped prism
An L-shaped prism is 10 cm long. Its front cross-section fits inside an 8 cm by 7 cm rectangle, with a 3 cm by 4 cm corner removed.

Find the area of the L-shaped end by subtracting the missing rectangle:
8×7−3×4=56−12=448\times 7-3\times 4=56-12=448×7−3×4=56−12=44There are two identical L-shaped ends:
2×44=882\times 44=882×44=88Walk around the L shape to find its perimeter:
8+3+3+4+5+7=308+3+3+4+5+7=308+3+3+4+5+7=30Find the total area of the rectangular side faces:
30×10=30030\times 10=30030×10=300Add the two ends and the side faces:
88+300=38888+300=38888+300=388The total surface area is 388 cm².
Walk around the outline
For composite prisms, trace the outside edge of the cross-section with your finger. Include the step edges.
Cylinder words
A cylinder has two equal circular faces and one curved face. The diameter is the full width through the centre of a circle; the radius is half the diameter.
A closed cylinder has a top and a bottom.
For a closed cylinder:
total surface area=2πr2+2πrh\text{total surface area}=2\pi r^2+2\pi rhtotal surface area=2πr2+2πrhHere, rrr is the radius and hhh is the height.
Surface area of a closed cylinder
A closed cylinder has diameter 50 cm and height 1.2 m. Find its surface area in m².

Convert the diameter to metres: 50 cm is 0.5 m, so the radius is 0.25 m.
Find the area of the two circular faces:
2πr2=2π×0.252=0.125π2\pi r^2=2\pi \times 0.25^2=0.125\pi2πr2=2π×0.252=0.125πFind the curved surface area:
2πrh=2π×0.25×1.2=0.6π2\pi rh=2\pi \times 0.25\times 1.2=0.6\pi2πrh=2π×0.25×1.2=0.6πAdd them:
0.125π+0.6π=0.725π≈2.280.125\pi+0.6\pi=0.725\pi\approx 2.280.125π+0.6π=0.725π≈2.28The surface area is about 2.28 m².
Using diameter as radius
If the question gives the diameter, halve it before using the cylinder formula.
Paint coverage
Coverage means the area that one pot of paint can cover.
In paint questions:
Converting area units
If paint coverage is in m², convert all lengths to metres before finding area. If you already have cm², divide by 10000 to get m².
How many pots for several boxes?
Four closed boxes are each 120 cm long, 50 cm wide and 40 cm high. One pot of paint covers 3 m². Work out how many pots are needed.

Convert the dimensions to metres: 120 cm is 1.2 m, 50 cm is 0.5 m, and 40 cm is 0.4 m.
Find the surface area of one box:
2(1.2×0.5)+2(1.2×0.4)+2(0.5×0.4)=2.562(1.2\times 0.5)+2(1.2\times 0.4)+2(0.5\times 0.4)=2.562(1.2×0.5)+2(1.2×0.4)+2(0.5×0.4)=2.56Four boxes need:
4×2.56=10.244\times 2.56=10.244×2.56=10.24Divide by the coverage per pot:
10.24÷3≈3.4110.24\div 3\approx 3.4110.24÷3≈3.41You need 4 pots, because you must buy whole pots.
In the exam
Label each face or use the prism formula so you do not miss any surfaces.
Check whether the shape has a top and bottom, especially cylinders and tanks.
Keep units consistent, then round paint pots up, not to the nearest whole number.
Check yourself
Can you explain why a cuboid has three pairs of equal faces?
For a prism, can you find the area and perimeter of the cross-section separately?
In a paint question, when do you need to round your answer up?
Test yourself with 5 quick questions on this guide. Answer them all correctly to complete it.
Test yourself on this topic, or move on to the next guide.
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