Write x2−6x+1x^2 - 6x + 1x2−6x+1 in the form (x+a)2+b(x + a)^2 + b(x+a)2+b where a a\,a and b b\,b are integers.
Hence, or otherwise, write down the coordinates of the turning point of the graph of y=x2−6x+1y = x^2 - 6x + 1y=x2−6x+1
