Starting with x0=1x_0 = 1x0=1, use the iteration formula xn+1=183xn−1\displaystyle x_{n+1} = \sqrt{\frac{18}{3x_n - 1}}xn+1=3xn−118 twice to find an estimate for the solution to 3x3−x2−18=03x^3 - x^2 - 18 = 03x3−x2−18=0
124 exam-style questions on CCEA GCSE Maths Iteration. Each one has a worked solution and a mark scheme showing where the marks go.