Writing a Ratio as a Fraction or Linear Function

What you'll learn

How to turn a ratio into fractions or algebraic expressions.
How to combine two ratios by matching a shared letter or quantity.
How to use a common multiplier to solve sharing and difference problems.
How to handle ratios involving “not red”, “not won”, or line segments.

1. Ratios, parts, and fractions

A ratio compares quantities by splitting them into parts. For example, if Sam and Tia share money in the ratio 3:2, then Sam gets 3 parts and Tia gets 2 parts.

Definition

Ratio parts

In a ratio like 3:2, the total number of parts is 3 + 2 = 5. The first person gets $35\frac{3}{5}$ of the total, and the second person gets $25\frac{2}{5}$ of the total.

Example

Using a ratio as fractions

Mia and Noah share £45 in the ratio 4:5. How much does Mia get?

A bar model shows the £45 split into 9 equal parts, with 4 parts for Mia and 5 parts for Noah.

Add the parts in the ratio.

Mia has 4 parts and Noah has 5 parts, so there are 9 parts altogether.
Write Mia’s share as a fraction of the total.
$fraction=49\text{Mia's fraction}=\frac{4}{9}$
Multiply the total by that fraction.
$49×45=20\frac{4}{9}\times 45=20$
Mia gets £20.

Key Idea

Ratio to fraction

To turn a part of a ratio into a fraction, put that part over the total number of parts.

2. Writing a ratio as a linear relationship

Sometimes you are given a ratio using letters, such as $A : B = 5 : 2$ .

This means $A$ and $B$ are linked by a fixed multiplier.

Definition

Linear relationship

A linear relationship between two quantities means one can be written as a constant multiple of the other, such as $A=52BA=\frac{5}{2}B$ .

If $A : B = 5 : 2$ , then:

$A$ is 5 parts.
$B$ is 2 parts.
So $A=52BA=\frac{5}{2}B$ .
Also $B=25AB=\frac{2}{5}A$ .

Example

Writing one variable in terms of another

Given $p : q = 7 : 3$ , write $p$ in terms of $q$ .

A paired bar model compares p as 7 equal parts with q as 3 equal parts.

Interpret the ratio.

$p$ has 7 parts and $q$ has 3 parts.
Compare $p$ to $q$ .
$pq=73\frac{p}{q}=\frac{7}{3}$
Multiply both sides by $q$ .
$p=73qp=\frac{7}{3}q$

Common Mistake

Reversing the fraction

If $p : q = 7 : 3$ , then $p=73qp=\frac{7}{3}q$ , not $p=37qp=\frac{3}{7}q$ . The order of the ratio matters.

3. Combining ratios with a shared quantity

A common GCSE question gives two ratios that share one letter. Your job is to make the shared letter have the same number of parts in both ratios.

For example, if $a : b = 2 : 5$ and $b : c = 3 : 4$ , the shared letter is $b$ . In the first ratio, $b$ is 5 parts. In the second ratio, $b$ is 3 parts. We need to make both into 15 parts.

Example

Finding a three-part ratio

Given $a : b = 2 : 5$ and $b : c = 3 : 4$ , find $a : b : c$ .

The shared quantity b is scaled to 15 parts so the two ratios can be combined.

Identify the shared quantity.

The shared quantity is $b$ .
Make the $b$ parts match.

In $a : b = 2 : 5$ , $b$ is 5 parts.
In $b : c = 3 : 4$ , $b$ is 3 parts.
The lowest common multiple of 5 and 3 is 15.
Scale the first ratio so $b = 15$ .
$a : b = 2 : 5 = 6 : 15$
Scale the second ratio so $b = 15$ .
$b : c = 3 : 4 = 15 : 20$
Combine the matching parts.
$a : b : c = 6 : 15 : 20$

Tip

Match the middle

When two ratios share a letter, focus on matching that shared letter first. The other values then fall into place.

4. Using a multiplier to solve amount problems

When actual amounts are involved, it is often easiest to write each amount as a multiple of one letter, usually $k$ .

Definition

Common multiplier

A common multiplier is a letter, often $k$ , used to turn ratio parts into real amounts. For example, a 4:3 ratio could mean $4 k$ and $3 k$ .

Example

Using a difference to find the multiplier

Dylan, Eva, and Finn share some counters. Dylan to Eva is in the ratio 5:2. Dylan to Finn is in the ratio 3:4. Finn gets 14 more counters than Dylan. How many counters does Eva get?

A combined ratio bar shows Dylan, Eva, and Finn as 15, 6, and 20 parts, with Finn 5 parts more than Dylan.

Write the two ratios.
$D : E = 5 : 2$ $D : F = 3 : 4$
Match the shared quantity, $D$ .

In the first ratio, $D$ is 5 parts.
In the second ratio, $D$ is 3 parts.
The lowest common multiple of 5 and 3 is 15.
Scale both ratios.
$D : E = 15 : 6$ $D : F = 15 : 20$
Combine the ratio.
$D : E : F = 15 : 6 : 20$
Use the difference between Finn and Dylan.

Finn has 20 parts and Dylan has 15 parts, so the difference is 5 parts.
This equals 14 counters.
Find one part.
$parts=145\text{ parts}=14$ $part=1451\text{ part}=\frac{14}{5}$
Find Eva’s amount.
$6×145=845=16.86\times \frac{14}{5}=\frac{84}{5}=16.8$

Common Mistake

Check for whole-number answers

If a question is about sweets, counters, or people, the final answer should usually be a whole number. If it is not, re-check the ratio or the difference.

5. Ratios involving “not” groups

A phrase like “red to not red” means:

red is one group
everything else is the other group

So if red to not red is 2:3, then red is 2 parts and the whole total is 5 parts.

Example

Using two 'not' ratios

In a bag there are red, blue, and green sweets. Red to not red is 3:7. Green to not green is 2:3. Find the ratio red:blue:green.

A 10-part total model shows red as 3 parts, green as 4 parts, and the remaining blue as 3 parts.

Turn each statement into a fraction of the total.

Red to not red is 3:7, so red is 3 parts out of 10.
$totalR=\frac{3}{10}\text{ of the total}$
Do the same for green.

Green to not green is 2:3, so green is 2 parts out of 5.
$totalG=\frac{2}{5}\text{ of the total}$
Use a total that works for both fractions.

The denominators are 10 and 5, so use 10 total parts.
Find red and green parts.
$R=310×10=3R=\frac{3}{10}\times 10=3$ $G=25×10=4G=\frac{2}{5}\times 10=4$
Find blue parts by subtracting from the total.
$B = 10 - 3 - 4 = 3$
Write the final ratio.
$R : B : G = 3 : 3 : 4$

Common Mistake

Forgetting the total

In “red:not red = 3:7”, the total is 10 parts, not 7 parts. The “not red” group is everything except red.

The ‘not red’ group is the complement of red, so the total contains both groups.

6. Line segment ratios

If points are in order on a straight line, a longer section may be made from smaller sections.

For points $A$ , $B$ , $C$ , and $D$ in order:

A straight-line diagram shows how AC and BD are made from adjacent smaller sections.

$A C = A B + B C$
$B D = B C + C D$

Example

Finding a ratio on a straight line

Points $A$ , $B$ , $C$ , and $D$ lie in order on a straight line. Given $A B : B D = 1 : 4$ and $A C : C D = 3 : 5$ , find $A B : B C : C D$ .

The line segment setup identifies the unknown sections x, y, and z and the two longer sections used in the ratios.

Let the three small sections be $A B = x$ , $B C = y$ , and $C D = z$ .
Use $A B : B D = 1 : 4$ .

Since $B D = B C + C D$ , this means:
$x : (y + z) = 1 : 4$
Use $A C : C D = 3 : 5$ .

Since $A C = A B + B C$ , this means:
$(x + y) : z = 3 : 5$
Choose a helpful value for $x$ from the first ratio.

If $x = 1$ , then $y + z = 4$ .
Use the second ratio.

$x + y$ must be 3 parts while $z$ is 5 parts, so scale until the equations fit.
From $x = 1$ and $y + z = 4$ , try multiplying the second ratio so $z = 5$ is too large, so scale both relationships instead.
A cleaner algebra method is to convert the ratios into equations.
$y + z = 4 x$ $5 (x + y) = 3 z$
Substitute $z = 4 x - y$ into the second equation.
$5 (x + y) = 3 (4 x - y)$ $5 x + 5 y = 12 x - 3 y$ $8 y = 7 x$
Choose values that make whole-number parts.

Let $x = 8$ , so $y = 7$ .
Then $z = 4 x - y = 32 - 7 = 25$ .
Write the ratio.
$A B : B C : C D = 8 : 7 : 25$

Exam technique

In the exam

Underline the shared quantity or the phrase “not”.
If two ratios share a letter, make that letter have the same number of parts.
If there is a total or a difference, use it only after you have found the combined ratio.

Self review

Check yourself

If $a : b = 3 : 4$ and $b : c = 2 : 5$ , what number should you make the $b$ parts equal to?
In “won to not won = 5:3”, what fraction of the games were won?
If $A : B = 4 : 7$ , can you write $A$ in terms of $B$ ?

What you'll learn

How to turn a ratio into fractions or algebraic expressions.
How to combine two ratios by matching a shared letter or quantity.
How to use a common multiplier to solve sharing and difference problems.
How to handle ratios involving “not red”, “not won”, or line segments.

1. Ratios, parts, and fractions

A ratio compares quantities by splitting them into parts. For example, if Sam and Tia share money in the ratio 3:2, then Sam gets 3 parts and Tia gets 2 parts.

Definition

Ratio parts

In a ratio like 3:2, the total number of parts is 3 + 2 = 5. The first person gets $35\frac{3}{5}$ of the total, and the second person gets $25\frac{2}{5}$ of the total.

Example

Using a ratio as fractions

Mia and Noah share £45 in the ratio 4:5. How much does Mia get?

A bar model shows the £45 split into 9 equal parts, with 4 parts for Mia and 5 parts for Noah.

Add the parts in the ratio.

Mia has 4 parts and Noah has 5 parts, so there are 9 parts altogether.
Write Mia’s share as a fraction of the total.
$fraction=49\text{Mia's fraction}=\frac{4}{9}$
Multiply the total by that fraction.
$49×45=20\frac{4}{9}\times 45=20$
Mia gets £20.

Key Idea

Ratio to fraction

To turn a part of a ratio into a fraction, put that part over the total number of parts.

2. Writing a ratio as a linear relationship

Sometimes you are given a ratio using letters, such as $A : B = 5 : 2$ .

This means $A$ and $B$ are linked by a fixed multiplier.

Definition

Linear relationship

A linear relationship between two quantities means one can be written as a constant multiple of the other, such as $A=52BA=\frac{5}{2}B$ .

If $A : B = 5 : 2$ , then:

$A$ is 5 parts.
$B$ is 2 parts.
So $A=52BA=\frac{5}{2}B$ .
Also $B=25AB=\frac{2}{5}A$ .

Example

Writing one variable in terms of another

Given $p : q = 7 : 3$ , write $p$ in terms of $q$ .

A paired bar model compares p as 7 equal parts with q as 3 equal parts.

Interpret the ratio.

$p$ has 7 parts and $q$ has 3 parts.
Compare $p$ to $q$ .
$pq=73\frac{p}{q}=\frac{7}{3}$
Multiply both sides by $q$ .
$p=73qp=\frac{7}{3}q$

Common Mistake

Reversing the fraction

If $p : q = 7 : 3$ , then $p=73qp=\frac{7}{3}q$ , not $p=37qp=\frac{3}{7}q$ . The order of the ratio matters.

3. Combining ratios with a shared quantity

A common GCSE question gives two ratios that share one letter. Your job is to make the shared letter have the same number of parts in both ratios.

For example, if $a : b = 2 : 5$ and $b : c = 3 : 4$ , the shared letter is $b$ . In the first ratio, $b$ is 5 parts. In the second ratio, $b$ is 3 parts. We need to make both into 15 parts.

Example

Finding a three-part ratio

Given $a : b = 2 : 5$ and $b : c = 3 : 4$ , find $a : b : c$ .

The shared quantity b is scaled to 15 parts so the two ratios can be combined.

Identify the shared quantity.

The shared quantity is $b$ .
Make the $b$ parts match.

In $a : b = 2 : 5$ , $b$ is 5 parts.
In $b : c = 3 : 4$ , $b$ is 3 parts.
The lowest common multiple of 5 and 3 is 15.
Scale the first ratio so $b = 15$ .
$a : b = 2 : 5 = 6 : 15$
Scale the second ratio so $b = 15$ .
$b : c = 3 : 4 = 15 : 20$
Combine the matching parts.
$a : b : c = 6 : 15 : 20$

Tip

Match the middle

When two ratios share a letter, focus on matching that shared letter first. The other values then fall into place.

4. Using a multiplier to solve amount problems

When actual amounts are involved, it is often easiest to write each amount as a multiple of one letter, usually $k$ .

Definition

Common multiplier

A common multiplier is a letter, often $k$ , used to turn ratio parts into real amounts. For example, a 4:3 ratio could mean $4 k$ and $3 k$ .

Example

Using a difference to find the multiplier

Dylan, Eva, and Finn share some counters. Dylan to Eva is in the ratio 5:2. Dylan to Finn is in the ratio 3:4. Finn gets 14 more counters than Dylan. How many counters does Eva get?

A combined ratio bar shows Dylan, Eva, and Finn as 15, 6, and 20 parts, with Finn 5 parts more than Dylan.

Write the two ratios.
$D : E = 5 : 2$ $D : F = 3 : 4$
Match the shared quantity, $D$ .

In the first ratio, $D$ is 5 parts.
In the second ratio, $D$ is 3 parts.
The lowest common multiple of 5 and 3 is 15.
Scale both ratios.
$D : E = 15 : 6$ $D : F = 15 : 20$
Combine the ratio.
$D : E : F = 15 : 6 : 20$
Use the difference between Finn and Dylan.

Finn has 20 parts and Dylan has 15 parts, so the difference is 5 parts.
This equals 14 counters.
Find one part.
$parts=145\text{ parts}=14$ $part=1451\text{ part}=\frac{14}{5}$
Find Eva’s amount.
$6×145=845=16.86\times \frac{14}{5}=\frac{84}{5}=16.8$

Common Mistake

Check for whole-number answers

If a question is about sweets, counters, or people, the final answer should usually be a whole number. If it is not, re-check the ratio or the difference.

5. Ratios involving “not” groups

A phrase like “red to not red” means:

red is one group
everything else is the other group

So if red to not red is 2:3, then red is 2 parts and the whole total is 5 parts.

Example

Using two 'not' ratios

In a bag there are red, blue, and green sweets. Red to not red is 3:7. Green to not green is 2:3. Find the ratio red:blue:green.

A 10-part total model shows red as 3 parts, green as 4 parts, and the remaining blue as 3 parts.

Turn each statement into a fraction of the total.

Red to not red is 3:7, so red is 3 parts out of 10.
$totalR=\frac{3}{10}\text{ of the total}$
Do the same for green.

Green to not green is 2:3, so green is 2 parts out of 5.
$totalG=\frac{2}{5}\text{ of the total}$
Use a total that works for both fractions.

The denominators are 10 and 5, so use 10 total parts.
Find red and green parts.
$R=310×10=3R=\frac{3}{10}\times 10=3$ $G=25×10=4G=\frac{2}{5}\times 10=4$
Find blue parts by subtracting from the total.
$B = 10 - 3 - 4 = 3$
Write the final ratio.
$R : B : G = 3 : 3 : 4$

Common Mistake

Forgetting the total

In “red:not red = 3:7”, the total is 10 parts, not 7 parts. The “not red” group is everything except red.

The ‘not red’ group is the complement of red, so the total contains both groups.

6. Line segment ratios

If points are in order on a straight line, a longer section may be made from smaller sections.

For points $A$ , $B$ , $C$ , and $D$ in order:

A straight-line diagram shows how AC and BD are made from adjacent smaller sections.

$A C = A B + B C$
$B D = B C + C D$

Example

Finding a ratio on a straight line

Points $A$ , $B$ , $C$ , and $D$ lie in order on a straight line. Given $A B : B D = 1 : 4$ and $A C : C D = 3 : 5$ , find $A B : B C : C D$ .

The line segment setup identifies the unknown sections x, y, and z and the two longer sections used in the ratios.

Let the three small sections be $A B = x$ , $B C = y$ , and $C D = z$ .
Use $A B : B D = 1 : 4$ .

Since $B D = B C + C D$ , this means:
$x : (y + z) = 1 : 4$
Use $A C : C D = 3 : 5$ .

Since $A C = A B + B C$ , this means:
$(x + y) : z = 3 : 5$
Choose a helpful value for $x$ from the first ratio.

If $x = 1$ , then $y + z = 4$ .
Use the second ratio.

$x + y$ must be 3 parts while $z$ is 5 parts, so scale until the equations fit.
From $x = 1$ and $y + z = 4$ , try multiplying the second ratio so $z = 5$ is too large, so scale both relationships instead.
A cleaner algebra method is to convert the ratios into equations.
$y + z = 4 x$ $5 (x + y) = 3 z$
Substitute $z = 4 x - y$ into the second equation.
$5 (x + y) = 3 (4 x - y)$ $5 x + 5 y = 12 x - 3 y$ $8 y = 7 x$
Choose values that make whole-number parts.

Let $x = 8$ , so $y = 7$ .
Then $z = 4 x - y = 32 - 7 = 25$ .
Write the ratio.
$A B : B C : C D = 8 : 7 : 25$

Exam technique

In the exam

Underline the shared quantity or the phrase “not”.
If two ratios share a letter, make that letter have the same number of parts.
If there is a total or a difference, use it only after you have found the combined ratio.

Self review

Check yourself

If $a : b = 3 : 4$ and $b : c = 2 : 5$ , what number should you make the $b$ parts equal to?
In “won to not won = 5:3”, what fraction of the games were won?
If $A : B = 4 : 7$ , can you write $A$ in terms of $B$ ?

What you'll learn

1. Ratios, parts, and fractions

2. Writing a ratio as a linear relationship

3. Combining ratios with a shared quantity

4. Using a multiplier to solve amount problems

5. Ratios involving “not” groups

6. Line segment ratios

Recap questions

Review Writing a Ratio as a Fraction or Linear Function by teaching Genie

Recap your knowledge with an interactive lesson

Remember key concepts with flashcards

Writing a Ratio as a Fraction or Linear Function

What you'll learn

1. Ratios, parts, and fractions

2. Writing a ratio as a linear relationship

3. Combining ratios with a shared quantity

4. Using a multiplier to solve amount problems

5. Ratios involving “not” groups

6. Line segment ratios

Recap questions

Review Writing a Ratio as a Fraction or Linear Function by teaching Genie

Recap your knowledge with an interactive lesson

Remember key concepts with flashcards

Writing a Ratio as a Fraction or Linear Function

What you'll learn

1. Ratios, parts, and fractions

2. Writing a ratio as a linear relationship

3. Combining ratios with a shared quantity

4. Using a multiplier to solve amount problems

5. Ratios involving “not” groups

6. Line segment ratios

Recap questions

Review Writing a Ratio as a Fraction or Linear Function by teaching Genie

Recap your knowledge with an interactive lesson

Remember key concepts with flashcards

Writing a Ratio as a Fraction or Linear Function Revision Guide

Writing a Ratio as a Fraction or Linear Function

What you'll learn

1. Ratios, parts, and fractions

2. Writing a ratio as a linear relationship

3. Combining ratios with a shared quantity

4. Using a multiplier to solve amount problems

5. Ratios involving “not” groups

6. Line segment ratios

Recap questions

Review Writing a Ratio as a Fraction or Linear Function by teaching Genie

Recap your knowledge with an interactive lesson

Remember key concepts with flashcards

Writing a Ratio as a Fraction or Linear Function Revision Guide