Revision notes for AQA GCSE Maths SOHCAHTOA (Trigonometry). Open the guide for explanations and worked examples. Written against the AQA GCSE Maths (8300) specification, so the content matches what's examinable rather than general Maths background.
Revision notes for AQA GCSE Maths SOHCAHTOA (Trigonometry). Open the guide for explanations and worked examples. Written against the AQA GCSE Maths (8300) specification, so the content matches what's examinable rather than general Maths background.
Welcome to Trigonometry! At Grade 5, you will learn how to connect the angles inside a right-angled triangle to the lengths of its sides.
What you'll learn:
Before doing any calculations, you must label your triangle correctly. The names of the sides change depending on which angle you are looking at. Let's call our angle θ\thetaθ (the Greek letter "theta").


The Three Sides
There are three main trigonometric ratios: sine, cosine, and tangent (shortened to sin, cos, and tan on your calculator). We use the memory trick SOH CAH TOA to remember the formulas.
SOH CAH TOA
Formula Triangles
If you struggle to rearrange formulas, you can put SOH, CAH, and TOA into formula triangles, just like you would for Speed, Distance, Time. Put the middle letter (O, A, or O) at the top of the triangle. Cover up what you want to find!

To find a missing side length, follow a simple 4-step process: label the sides, pick your formula, substitute the numbers, and solve.
Finding a side (numerator)
A right-angled triangle has an angle of 35°. The hypotenuse is 20 cm. Find the length of the side opposite the 35° angle, labelled xxx.

Label the sides. We want the Opposite (which is xxx), and we know the Hypotenuse (which is 20).
Choose the formula. We have O and H, which means we need SOH.
Write out the formula and substitute the values:
sin(35∘)=x20\sin(35^\circ) = \frac{x}{20}sin(35∘)=20xSolve for xxx by multiplying both sides by 20. Type this into your calculator to get the final answer:
x=20×sin(35∘)x=11.47 cm (to 2 d.p.)\begin{aligned} x &= 20 \times \sin(35^\circ) \\ x &= 11.47\text{ cm (to 2 d.p.)} \end{aligned}xx=20×sin(35∘)=11.47 cm (to 2 d.p.)Sometimes, the side you are trying to find ends up on the bottom (the denominator) of the fraction. This just adds one extra step to your solving process.
Finding a side (denominator)
A right-angled triangle has an angle of 42°. The side opposite the angle is 11 cm. Find the length of the adjacent side, xxx.

Label the sides. We know the Opposite (11) and we want the Adjacent (xxx).
Choose the formula. O and A means we use TOA.
Substitute the values:
tan(42∘)=11x\tan(42^\circ) = \frac{11}{x}tan(42∘)=x11To solve, first multiply by xxx to get it off the bottom, then divide by tan(42∘)\tan(42^\circ)tan(42∘). Essentially, xxx and tan(42∘)\tan(42^\circ)tan(42∘) swap places:
x×tan(42∘)=11x=11tan(42∘)x=12.22 cm (to 2 d.p.)\begin{aligned} x \times \tan(42^\circ) &= 11 \\ x &= \frac{11}{\tan(42^\circ)} \\ x &= 12.22\text{ cm (to 2 d.p.)} \end{aligned}x×tan(42∘)xx=11=tan(42∘)11=12.22 cm (to 2 d.p.)If you know two side lengths, you can find a missing angle. You still use SOH CAH TOA, but at the end, you need to use the inverse trigonometric functions (sin−1\sin^{-1}sin−1, cos−1\cos^{-1}cos−1, or tan−1\tan^{-1}tan−1) on your calculator. You usually get these by pressing the SHIFT or 2ND button before the sin, cos, or tan button.
Finding a missing angle
A right-angled triangle has an adjacent side of 9 cm and an opposite side of 5 cm. Calculate the size of the angle θ\thetaθ.

Label the sides. We have the Opposite (5) and the Adjacent (9).
Choose the formula. O and A means we need TOA.
Substitute the values:
tan(θ)=59\tan(\theta) = \frac{5}{9}tan(θ)=95Use the inverse tan function to find the angle. Type this exactly into your calculator:
θ=tan−1(59)θ=29.1∘ (to 1 d.p.)\begin{aligned} \theta &= \tan^{-1}\left(\frac{5}{9}\right) \\ \theta &= 29.1^\circ \text{ (to 1 d.p.)} \end{aligned}θθ=tan−1(95)=29.1∘ (to 1 d.p.)Dividing by the word 'tan'
Remember that "tan" is a function, not a number. You cannot isolate θ\thetaθ by dividing by the word "tan". You must use the inverse function tan−1\tan^{-1}tan−1 to extract the angle!
In the exam
Check yourself
Test yourself with 5 quick questions on this guide. Answer them all correctly to complete it.
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