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Question 5

An audio engineer is setting up a digital recording system to record a live performance in stereo (2 channels). The audio is sampled at a frequency of 96 kHz96\text{ kHz}96 kHz with a sample resolution of 24 bits24\text{ bits}24 bits per sample.

Which of the following expressions correctly calculates the storage capacity required, in mebibytes (MiB\text{MiB}MiB), to store an uncompressed 15-minute15\text{-minute}15-minute audio recording?

A
2×96,000×24×158×10242 \frac{2 \times 96,000 \times 24 \times 15}{8 \times 1024^2} 8×102422×96,000×24×15​
B
2×96,000×24×9008×10242 \frac{2 \times 96,000 \times 24 \times 900}{8 \times 1024^2} 8×102422×96,000×24×900​
C
96,000×24×9008×10242 \frac{96,000 \times 24 \times 900}{8 \times 1024^2} 8×1024296,000×24×900​
D
2×96,000×24×90010242 \frac{2 \times 96,000 \times 24 \times 900}{1024^2} 102422×96,000×24×900​
Markscheme

Data storage Questions

  1. GCSE
  2. /Computer Science
  3. /Data storage

41 exam-style questions on OCR GCSE Computer Science Data storage. Each one has a worked solution and a mark scheme showing where the marks go.

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