questions","basePath":"/gcse/computer-science/edexcel/truth-tables/questions","formulaUrl":null,"initialIndex":12,"initialQuestionWindow":[{"id":"c194728c-c1ba-4547-9fe7-474f0f896386","revisionId":"40575275-528e-4cff-9bca-c86f054dc5bf","questionNumber":null,"questionType":"LA","specification":"A safety system in an industrial chemical plant monitors three status signals: pressure sensor $P$, temperature sensor $Q$, and flow sensor $R$. A value of $1$ indicates a normal state, while $0$ indicates a critical alert state.\n\nThe system uses automated logic gates to process these inputs.","difficulty":3,"difficultyBand":"medium","totalMarks":6,"sourceTitle":null,"calculatorUse":null,"parts":[{"id":"2b14c4ee-e4cd-4209-ab02-ce00194ab0ee","label":null,"content":"Complete the truth table below by determining the missing binary values for **[i]** to **[vi]**.\n\n| P | Q | R | P AND Q | (P AND Q) OR (NOT R) |\n|---|---|---|---------|----------------------|\n| 0 | 0 | 0 | **[i]** | 1 |\n| 0 | 0 | 1 | 0 | **[ii]** |\n| 0 | 1 | 0 | 0 | **[iii]** |\n| 0 | 1 | 1 | 0 | 0 |\n| 1 | 0 | 0 | 0 | **[iv]** |\n| 1 | 0 | 1 | 0 | 0 |\n| 1 | 1 | 0 | **[v]** | 1 |\n| 1 | 1 | 1 | 1 | **[vi]** |","markscheme":"- Evaluates $\\text{P AND Q}$ for $P = 0, Q = 0$ to find $\\mathbf{[i]} = 0$ B1\n- Evaluates $(\\text{P AND Q}) \\text{ OR (NOT R)}$ for $(\\text{P AND Q}) = 0, R = 1$ to find $\\mathbf{[ii]} = 0$ B1\n- Evaluates $(\\text{P AND Q}) \\text{ OR (NOT R)}$ for $(\\text{P AND Q}) = 0, R = 0$ to find $\\mathbf{[iii]} = 1$ B1\n- Evaluates $(\\text{P AND Q}) \\text{ OR (NOT R)}$ for $(\\text{P AND Q}) = 0, R = 0$ to find $\\mathbf{[iv]} = 1$ B1\n- Evaluates $\\text{P AND Q}$ for $P = 1, Q = 1$ to find $\\mathbf{[v]} = 1$ B1\n- Evaluates $(\\text{P AND Q}) \\text{ OR (NOT R)}$ for $(\\text{P AND Q}) = 1, R = 1$ to find $\\mathbf{[vi]} = 1$ B1","marks":6,"order":0,"markingRubric":null,"explanation":null,"options":[]}],"options":[],"explanation":null,"firstAttemptFullMarks":null},{"id":"c42072df-d7bb-49e0-94f6-7ba10ed84b09","revisionId":"e2d567d4-e0ae-41a9-b818-4fa6fb04b618","questionNumber":null,"questionType":"LA","specification":"","difficulty":5,"difficultyBand":"medium","totalMarks":4,"sourceTitle":null,"calculatorUse":null,"parts":[{"id":"ea6b2fb4-be75-4020-a3ff-cd5f177f5ef1","label":null,"content":"Complete the truth table for the logic expression `NOT (A AND B)`.\n\n| A | B | NOT (A AND B) |\n| :---: | :---: | :---: |\n| 0 | 0 | **[ P ]** |\n| 1 | **[ Q ]** | 0 |\n| **[ R ]** | 1 | 1 |\n| 1 | 0 | **[ S ]** |","markscheme":"- Identifies that for $P$, $A=0$ and $B=0 \\implies \\text{NOT}(0 \\text{ AND } 0) = 1$, so $P = 1$ B1\n- Identifies that for $Q$, $\\text{NOT}(1 \\text{ AND } Q) = 0 \\implies 1 \\text{ AND } Q = 1 \\implies Q = 1$ B1\n- Identifies that for $R$, $\\text{NOT}(R \\text{ AND } 1) = 1 \\implies R \\text{ AND } 1 = 0 \\implies R = 0$ B1\n- Identifies that for $S$, $A=1$ and $B=0 \\implies \\text{NOT}(1 \\text{ AND } 0) = 1$, so $S = 1$ B1","marks":4,"order":0,"markingRubric":null,"explanation":null,"options":[]}],"options":[],"explanation":null,"firstAttemptFullMarks":null}],"subjectCode":"gcse_computer_science","summaries":[{"id":"04dbaace-ee83-49d7-b4c9-d4359d0e1992","difficultyBand":"medium","calculatorUse":null},{"id":"1102f81e-b0d5-4c33-baaf-909165cc5026","difficultyBand":"easy","calculatorUse":null},{"id":"36f7b7ef-0d97-4589-972f-1cd3778f1865","difficultyBand":"medium","calculatorUse":null},{"id":"3f15b57a-d72e-4a87-b712-4ada2973db66","difficultyBand":"medium","calculatorUse":null},{"id":"445c0e48-f482-4d4a-9c70-9bc7a532ac01","difficultyBand":"medium","calculatorUse":null},{"id":"50bcefff-3f75-4aa0-a0d6-36dbdde5926a","difficultyBand":"medium","calculatorUse":null},{"id":"598b320a-5764-42f7-8fec-8da54976d225","difficultyBan

A	B	NOT (A AND B)
0	0	[ P ]
1	[ Q ]	0
[ R ]	1	1
1	0	[ S ]

A	B	NOT (A AND B)
0	0	[ P ]
1	[ Q ]	0
[ R ]	1	1
1	0	[ S ]

Truth tables

Question 8

Truth tables Questions

Truth tables

Question 8

Truth tables Questions