Group 7 elements (halogens) react with halides in solution.
Bromine reacts with potassium iodide to form potassium bromide and iodine.
Br2(aq)+2KI(aq)→2KBr(aq)+I2(aq)\text{Br}_2(\text{aq}) + 2\text{KI}(\text{aq}) \rightarrow 2\text{KBr}(\text{aq}) + \text{I}_2(\text{aq})Br2(aq)+2KI(aq)→2KBr(aq)+I2(aq)
Describe what you would observe in the reaction.
This is the half equation that shows what happens to bromine. Br2+2e−→2Br−\text{Br}_2 + 2\text{e}^- \rightarrow 2\text{Br}^-Br2+2e−→2Br− Explain why this half equation shows reduction.
Write the balanced half equation for the reaction of the iodide ions.
Bromine displaces iodine from potassium iodide because bromine is more reactive than iodine. Explain why bromine is more reactive than iodine.
The diagram shows the mass spectrum for a compound containing bromine.

State the relative molecular mass of the heavier molecular ion of this compound.
Instrumental methods of analysis, such as mass spectrometry, have advantages over simple chemical methods of analysis. State two advantages of instrumental methods of analysis.