A heavy fraction of crude oil containing hexacosane, C26H54\text{C}_{26}\text{H}_{54}C26H54, is cracked to produce tetradecane, C14H30\text{C}_{14}\text{H}_{30}C14H30, and another useful hydrocarbon as shown below:
C26H54→C14H30+3 ………… \text{C}_{26}\text{H}_{54} \rightarrow \text{C}_{14}\text{H}_{30} + 3 \, \dots\dots\dots\dots C26H54→C14H30+3…………Complete the balanced symbol equation for this cracking reaction by finding the missing chemical formula.
A student has two hydrocarbons, Compound A (C3H8\text{C}_3\text{H}_8C3H8) and Compound B (C3H6\text{C}_3\text{H}_6C3H6). A few drops of orange bromine water are added to a sample of each compound.
Explain why Compound B decolourises bromine water but Compound A does not.
Write the balanced symbol equation for the reaction of Compound B with bromine, Br2\text{Br}_2Br2.
83 exam-style questions on OCR GCSE Chemistry Organic chemistry. Each one has a worked solution and a mark scheme showing where the marks go.