Introducing chemical reactions

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Question 1
Hard

Lead oxide can be reduced to lead by reaction with hydrogen:

PbO+H2→Pb+H2O\text{PbO} + \text{H}_2 \rightarrow \text{Pb} + \text{H}_2\text{O}PbO+H2​→Pb+H2​O

A reaction mixture contains 11.15 g11.15\text{ g}11.15 g of lead oxide and 0.30 g0.30\text{ g}0.30 g of hydrogen.

10.35 g10.35\text{ g}10.35 g of lead and 0.90 g0.90\text{ g}0.90 g of water are made.

Calculate the number of moles of each substance to determine the limiting reactant in this reaction.

Explain your choice.

The relative atomic mass of Pb\text{Pb}Pb is 207207207, of O\text{O}O is 161616, and of H\text{H}H is 111.

  • Number of moles of PbO=……………………………………………………\text{PbO} = \dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dotsPbO=……………………………………………………
  • Number of moles of H2=……………………………………………………\text{H}_2 = \dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dotsH2​=……………………………………………………
  • Number of moles of Pb=……………………………………………………\text{Pb} = \dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dotsPb=……………………………………………………
  • Number of moles of H2O=……………………………………………………\text{H}_2\text{O} = \dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dotsH2​O=……………………………………………………

The limiting reactant is ………………………………\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots……………………………… because ……………………………………………………………………………………………………\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots……………………………………………………………………………………………………

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Introducing chemical reactions Questions

  1. GCSE
  2. /Chemistry
  3. /Introducing chemical reactions