Using the equation for the decomposition of dinitrogen pentoxide:
2N2O5(g)→4NO2(g)+O2(g) 2\text{N}_2\text{O}_5(\text{g}) \rightarrow 4\text{NO}_2(\text{g}) + \text{O}_2(\text{g}) 2N2O5(g)→4NO2(g)+O2(g)calculate the maximum volume of gaseous products, in cm3\text{cm}^3cm3, that could be formed by the complete reaction of 340 cm3 of dinitrogen pentoxide.
(Assume all volumes of gases are measured under the same conditions of temperature and pressure.)
157 exam-style questions on Edexcel GCSE Chemistry 6.2 Quantitative analysis, covering 6.2.1 Concentration in mol dm⁻³ and titration calculations, 6.2.2 Percentage yield and why actual yield falls short, 6.2.3 Atom economy of a reaction, 6.2.4 Choosing a reaction pathway, and 6.2.5 Molar volume of gases and Avogadro's law. Each one has a worked solution and a mark scheme showing where the marks go.