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6.2 Quantitative analysis

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Question 42

A process chemist calculates the amount of solute in 75.0 cm3 of copper nitrate solution. The chemist substitutes 75.0 directly into

amount in mol=concentration in mol dm−3×volume \text{amount in mol}=\text{concentration in mol dm}^{-3}\times\text{volume} amount in mol=concentration in mol dm−3×volume

and reports the answer in mol.

Which statement describes the amount the chemist reports?

[1]
A

The value is one thousand times too large.

B

The value is one million times too large.

C

The value is correct because the volume units cancel.

D

The value is one thousand times too small.

Markscheme

6.2 Quantitative analysis Questions

  1. GCSE
  2. /Chemistry
  3. /6.2 Quantitative analysis

151 exam-style questions on Edexcel GCSE Chemistry 6.2 Quantitative analysis, covering 6.2.1 Concentration in mol dm⁻³ and titration calculations, 6.2.2 Percentage yield and why actual yield falls short, 6.2.3 Atom economy of a reaction, 6.2.4 Choosing a reaction pathway, and 6.2.5 Molar volume of gases and Avogadro's law. Each one has a worked solution and a mark scheme showing where the marks go.

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