Hydrogen reacts with chlorine to form hydrogen chloride.
H2(g)+Cl2(g)→2HCl(g)\mathrm{H_2(g) + Cl_2(g) \rightarrow 2HCl(g)}H2(g)+Cl2(g)→2HCl(g)
Hydrogen is in excess.
Relative formula masses: Cl2=71\mathrm{Cl_2} = 71Cl2=71 and HCl=36.5\mathrm{HCl} = 36.5HCl=36.5.
Calculate the maximum mass of hydrogen chloride produced when 21.3 g of chlorine reacts completely.
151 exam-style questions on Edexcel GCSE Chemistry 6.2 Quantitative analysis, covering 6.2.1 Concentration in mol dm⁻³ and titration calculations, 6.2.2 Percentage yield and why actual yield falls short, 6.2.3 Atom economy of a reaction, 6.2.4 Choosing a reaction pathway, and 6.2.5 Molar volume of gases and Avogadro's law. Each one has a worked solution and a mark scheme showing where the marks go.