Using the equation for the decomposition of ammonia:
2NH3(g)→N2(g)+3H2(g) 2\text{NH}_3(\text{g}) \rightarrow \text{N}_2(\text{g}) + 3\text{H}_2(\text{g}) 2NH3(g)→N2(g)+3H2(g)calculate the maximum volume of gaseous products, in dm3\text{dm}^3dm3, that could be formed by the complete reaction of 450 dm3 of ammonia.
(Assume all volumes of gases are measured under the same conditions of temperature and pressure.)
157 exam-style questions on Edexcel GCSE Chemistry 6.2 Quantitative analysis, covering 6.2.1 Concentration in mol dm⁻³ and titration calculations, 6.2.2 Percentage yield and why actual yield falls short, 6.2.3 Atom economy of a reaction, 6.2.4 Choosing a reaction pathway, and 6.2.5 Molar volume of gases and Avogadro's law. Each one has a worked solution and a mark scheme showing where the marks go.