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6.2 Quantitative analysis

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Question 18

A factory can make calcium chloride by two routes.

Route 1 uses the reaction:

CaCO3(s)+2HCl(aq)→CaCl2(aq)+H2O(l)+CO2(g)\mathrm{CaCO_{3}(s) + 2HCl(aq) \rightarrow CaCl_{2}(aq) + H_{2}O(l) + CO_{2}(g)}CaCO3​(s)+2HCl(aq)→CaCl2​(aq)+H2​O(l)+CO2​(g)

Route 2 uses the reaction:

Ca(OH)2(s)+2HCl(aq)→CaCl2(aq)+2H2O(l)\mathrm{Ca(OH)_{2}(s) + 2HCl(aq) \rightarrow CaCl_{2}(aq) + 2H_{2}O(l)}Ca(OH)2​(s)+2HCl(aq)→CaCl2​(aq)+2H2​O(l)

The relative masses of the products shown in the equations are summarised in the table.

QuantityRoute 1Route 2
relative mass of calcium chloride111111
combined relative mass of the other products6236

The atom economy is calculated using:

atom economy=relative mass of desired producttotal relative mass of all products×100 \text{atom economy} = \frac{\text{relative mass of desired product}}{\text{total relative mass of all products}} \times 100 atom economy=total relative mass of all productsrelative mass of desired product​×100

The table gives operating data for the two routes.

FeatureRoute 1Route 2
percentage yield92%79%
maximum output of calcium chloride84 tonnes per day52 tonnes per day
use of other productscarbon dioxide and water are not reusedwater is fed back into the process
cost of producing one tonne of calcium chloride£360£320
a.

Calculate the total relative mass of all the products in each route.

[2]
b.

Use the atom economy expression and your answers to part (a) to work out the atom economy of each route.

[2]
c.

The factory must choose one route for a period when orders for calcium chloride are high. Evaluate the choice it should make.

[6]
Markscheme

6.2 Quantitative analysis Questions

  1. GCSE
  2. /Chemistry
  3. /6.2 Quantitative analysis

151 exam-style questions on Edexcel GCSE Chemistry 6.2 Quantitative analysis, covering 6.2.1 Concentration in mol dm⁻³ and titration calculations, 6.2.2 Percentage yield and why actual yield falls short, 6.2.3 Atom economy of a reaction, 6.2.4 Choosing a reaction pathway, and 6.2.5 Molar volume of gases and Avogadro's law. Each one has a worked solution and a mark scheme showing where the marks go.

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