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6.2 Quantitative analysis

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Question 9

A student prepares potassium nitrate crystals. The theoretical yield of pure, dry potassium nitrate is 18.5 g. The student collects 14.8 g of pure, dry potassium nitrate.

Calculate the mass of crystals collected as a percentage of the theoretical yield.

Use the equation:

percentage yield=actual yieldtheoretical yield×100\displaystyle \text{percentage yield} = \frac{\text{actual yield}}{\text{theoretical yield}} \times 100percentage yield=theoretical yieldactual yield​×100

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Markscheme

6.2 Quantitative analysis Questions

  1. GCSE
  2. /Chemistry
  3. /6.2 Quantitative analysis

151 exam-style questions on Edexcel GCSE Chemistry 6.2 Quantitative analysis, covering 6.2.1 Concentration in mol dm⁻³ and titration calculations, 6.2.2 Percentage yield and why actual yield falls short, 6.2.3 Atom economy of a reaction, 6.2.4 Choosing a reaction pathway, and 6.2.5 Molar volume of gases and Avogadro's law. Each one has a worked solution and a mark scheme showing where the marks go.

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