Carbon monoxide is oxidised to carbon dioxide in a gas-cleaning process.
2CO(g)+O2(g)→2CO2(g) \mathrm{2CO(g) + O_{2}(g) \rightarrow 2CO_{2}(g)} 2CO(g)+O2(g)→2CO2(g)A batch of gas contains only carbon monoxide and oxygen. The mixture is ignited and then allowed to return to room temperature and pressure (rtp).
For these theoretical calculations, assume that all of the limiting reactant is converted into product. All gas volumes are measured at rtp.
| Quantity | Value |
|---|---|
| Total volume of the mixture before reaction | 12.0 dm312.0\ \mathrm{dm^{3}}12.0 dm3 |
| Volume of oxygen before reaction | 4.80 dm34.80\ \mathrm{dm^{3}}4.80 dm3 |
| Relative formula mass of carbon monoxide, CO\mathrm{CO}CO | 28 |
| Molar volume at rtp | 24 dm324\ \mathrm{dm^{3}}24 dm3 per mole |
Calculate the mass of carbon monoxide in the mixture before the reaction.
State which reactant is limiting and calculate the volume of carbon dioxide formed.
Calculate the total volume of gas after the reaction and explain why it is less than the total volume before the reaction.
Explain why the balancing numbers in the equation can be used to compare the gas volumes directly.
151 exam-style questions on Edexcel GCSE Chemistry 6.2 Quantitative analysis, covering 6.2.1 Concentration in mol dm⁻³ and titration calculations, 6.2.2 Percentage yield and why actual yield falls short, 6.2.3 Atom economy of a reaction, 6.2.4 Choosing a reaction pathway, and 6.2.5 Molar volume of gases and Avogadro's law. Each one has a worked solution and a mark scheme showing where the marks go.