A student uses a pipette to transfer 30.0 cm330.0\,\mathrm{cm^{3}}30.0cm3 of 0.0800 mol dm−30.0800\,\mathrm{mol\,dm^{-3}}0.0800moldm−3 potassium hydroxide solution into a conical flask. The burette contains 0.120 mol dm−30.120\,\mathrm{mol\,dm^{-3}}0.120moldm−3 oxalic acid solution.
The equation for the reaction during the titration is:
H2C2O4(aq)+2KOH(aq)→K2C2O4(aq)+2H2O(l)\mathrm{H_{2}C_{2}O_{4}(aq) + 2KOH(aq) \rightarrow K_{2}C_{2}O_{4}(aq) + 2H_{2}O(l)}H2C2O4(aq)+2KOH(aq)→K2C2O4(aq)+2H2O(l)
What volume of oxalic acid exactly neutralises the potassium hydroxide?
40.0 cm340.0\,\mathrm{cm^{3}}40.0cm3
10.0 cm310.0\,\mathrm{cm^{3}}10.0cm3
20.0 cm320.0\,\mathrm{cm^{3}}20.0cm3
30.0 cm330.0\,\mathrm{cm^{3}}30.0cm3
151 exam-style questions on Edexcel GCSE Chemistry 6.2 Quantitative analysis, covering 6.2.1 Concentration in mol dm⁻³ and titration calculations, 6.2.2 Percentage yield and why actual yield falls short, 6.2.3 Atom economy of a reaction, 6.2.4 Choosing a reaction pathway, and 6.2.5 Molar volume of gases and Avogadro's law. Each one has a worked solution and a mark scheme showing where the marks go.