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2.3 Ionic bonding

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Question 14
H

Rubidium is in group 1 and selenium is in group 6 of the periodic table. Rubidium reacts with selenium to form the ionic compound rubidium selenide.

Which describes how rubidium selenide forms from its atoms?

[1]
A

Each Rb atom loses one electron and each Se atom gains one, forming RbSe\mathrm{RbSe}RbSe

B

Each Rb atom loses two electrons and each Se atom gains two, forming RbSe\mathrm{RbSe}RbSe

C

Each Rb atom loses one electron and each Se atom gains two, forming Rb2Se\mathrm{Rb_{2}Se}Rb2​Se

D

Each Rb atom loses one electron and each Se atom gains two, forming RbSe2\mathrm{RbSe_{2}}RbSe2​

Markscheme

2.3 Ionic bonding Questions

  1. GCSE
  2. /Chemistry
  3. /2.3 Ionic bonding

56 exam-style questions on Edexcel GCSE Chemistry 2.3 Ionic bonding, covering 2.3.1 Ions and the formation of ionic bonds, 2.3.2 Naming and deducing formulae of ionic compounds, and 2.3.3 Giant ionic lattices. Each one has a worked solution and a mark scheme showing where the marks go.

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