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6.2.3 Atom economy of a reaction

6.2.3 Atom economy of a reaction

Atom economy measures how much of the product mass is wanted

Definition

Atom economy

The mass of the desired product as a percentage of the total mass of product formed.

  1. A reaction usually makes more than one product, and only one of them is the desired product.
  2. Atom economy compares the mass of that product with the mass of everything formed: atom economy=Mr of the desired productsum of the Mr of all products×100\text{atom economy} = \frac{M_r \text{ of the desired product}}{\text{sum of the } M_r \text{ of all products}} \times 100atom economy=sum of the Mr​ of all productsMr​ of the desired product​×100
  3. The masses come from the balanced equation, with each MrM_rMr​ multiplied by its balancing number.
  4. A high atom economy means little of the starting material ends up as waste.
  5. The answer is a percentage and carries no unit.
Key Idea

Atom economy is fixed by the equation alone, so it is the same however carefully the reaction is carried out.

Working out an atom economy step by step

  1. Write the balanced equation and identify which product is wanted.
  2. Find the MrM_rMr​ of that product and multiply it by its balancing number.
  3. Do the same for every other product, then add all the products together.
  4. Divide the desired figure by the total and multiply by 100100100.
  5. The reactants never enter the calculation, since conservation of mass makes their total the same.
Common Mistake
  • Leaving a by-product out of the total gives an atom economy that is falsely high.
  • A balancing number multiplies the MrM_rMr​ before anything is added.

A worked atom economy: extracting iron

  1. The equation for reducing iron(III) oxide with carbon monoxide is: Fe2O3+3CO→2Fe+3CO2\text{Fe}_2\text{O}_3 + 3\text{CO} \rightarrow 2\text{Fe} + 3\text{CO}_2Fe2​O3​+3CO→2Fe+3CO2​
  2. The desired product is iron, of ArA_rAr​ 565656: 2×56=1122 \times 56 = 1122×56=112
  3. The only by-product is carbon dioxide, of MrM_rMr​ 444444: 3×44=1323 \times 44 = 1323×44=132
  4. The atom economy follows from the two totals: 112112+132×100=45.9%\frac{112}{112 + 132} \times 100 = 45.9\%112+132112​×100=45.9%
  5. Less than half the mass formed is iron, and the rest leaves the process as carbon dioxide.
Example
  • One product only: an addition reaction that makes a single product has an atom economy of 100%100\%100%.
  • Two products of similar mass: the atom economy lands near 50%50\%50%.

Why a high atom economy matters

  1. A reaction with a low atom economy converts much of its raw material into waste.
  2. That waste has to be separated, treated or disposed of, which costs money.
  3. Raw materials are often finite, so wasting them shortens the supply.
  4. A route with a higher atom economy is usually more sustainable for the same product.
  5. A useful by-product softens the objection, because the waste can be sold rather than discarded.
Note

Atom economy and percentage yield measure different things, and a reaction can score well on one and badly on the other.

Comparing two routes to the same product

  1. Two reactions that give the same product can have very different atom economies.
  2. The route that forms fewer by-products keeps more of the mass in the wanted product.
  3. An addition reaction, which joins everything into one product, scores highest of all.
  4. A route with a lower atom economy may still be chosen if it is faster or cheaper to run.
  5. Comparing routes fairly means quoting both figures and the reason for preferring one.
Self review
  • What does the atom economy of a reaction compare?
  • Why do the reactants not appear in the calculation?
  • What is the atom economy of a reaction that forms only one product?
  • Calculate the atom economy for iron in Fe2O3+3CO→2Fe+3CO2\text{Fe}_2\text{O}_3 + 3\text{CO} \rightarrow 2\text{Fe} + 3\text{CO}_2Fe2​O3​+3CO→2Fe+3CO2​.
  • Give two reasons why a high atom economy is preferred.
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Atom economy measures how much of the mass of the products is the desired product. It is expressed as a percentage, so it has no unit.

atom economy=balancing number of desired product×Mr of desired productsum of (balancing number×Mr) for all products×100 \text{atom economy} = \frac{\text{balancing number of desired product} \times M_r\text{ of desired product}}{\text{sum of }(\text{balancing number} \times M_r)\text{ for all products}} \times 100 atom economy=sum of (balancing number×Mr​) for all productsbalancing number of desired product×Mr​ of desired product​×100

Use the balanced equation and multiply each product's MrM_rMr​ by its balancing number. A high atom economy means that little of the starting material becomes waste. The value is fixed by the balanced equation, so it does not change when the reaction is carried out more carefully.

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Atom economy is the mass of the [     ] as a percentage of the total product mass.

6.2.3 Atom economy of a reaction Revision Guide

  1. GCSE
  2. /Chemistry
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Revision notes for Edexcel GCSE Chemistry 6.2.3 Atom economy of a reaction: explanations and worked examples.

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