Fe2O3+3CO→2Fe+3CO2\mathrm{Fe_2O_3 + 3CO \rightarrow 2Fe + 3CO_2}Fe2O3+3CO→2Fe+3CO2
Relative formula mass (MrM_rMr): Fe2O3\mathrm{Fe_2O_3}Fe2O3 = 160
Relative atomic mass (ArA_rAr): Fe = 56
In an experiment, 32.0 g of iron(III) oxide produced 16.8 g of iron.
What is the percentage yield of iron?
37.5 %
52.5 %
75.0 %
150 %
39 exam-style questions on AQA GCSE Chemistry 3.3 Yield and atom economy of chemical reactions, covering 3.3.1a Percentage yield, 3.3.1b Theoretical mass of a product, 3.3.2a Atom economy, and 3.3.2b Choosing a reaction pathway. Each one has a worked solution and a mark scheme showing where the marks go.