A technician added 24.0 cm3 of 0.0500 mol/dm3 barium hydroxide solution to 15.0 cm3 of nitric acid. The solutions exactly neutralised each other. The equation for the reaction is Ba(OH)2+2HNO3→Ba(NO3)2+2H2O\text{Ba(OH)}_2 + 2\text{HNO}_3 \rightarrow \text{Ba(NO}_3)_2 + 2\text{H}_2\text{O}Ba(OH)2+2HNO3→Ba(NO3)2+2H2O. What is the concentration of the nitric acid?
0.0400 mol/dm30.0400\ \text{mol/dm}^30.0400 mol/dm3
0.0800 mol/dm30.0800\ \text{mol/dm}^30.0800 mol/dm3
0.160 mol/dm30.160\ \text{mol/dm}^30.160 mol/dm3
0.320 mol/dm30.320\ \text{mol/dm}^30.320 mol/dm3
106 exam-style questions on AQA GCSE Chemistry 3.4 Using concentrations of solutions in mol/dm3, covering 3.4.1 Concentration in mol/dm3. Each one has a worked solution and a mark scheme showing where the marks go.