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3.4 Using concentrations of solutions in mol/dm3

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Question 1

An analyst used sodium carbonate solution to find the concentration of a sample of hydrochloric acid. A 25.0 cm3 portion of the acid reacted completely with 16.0 cm3 of 0.150 mol/dm3 sodium carbonate solution.

The equation for the reaction is:

Na2CO3+2HCl→2NaCl+H2O+CO2\text{Na}_2\text{CO}_3 + 2\text{HCl} \rightarrow 2\text{NaCl} + \text{H}_2\text{O} + \text{CO}_2Na2​CO3​+2HCl→2NaCl+H2​O+CO2​

a.

Calculate the amount of sodium carbonate, in mol\text{mol}mol, that reacted with the acid.

[2]
b.

Calculate the concentration of the hydrochloric acid. Give your answer in mol/dm3\text{mol/dm}^3mol/dm3.

[3]
Markscheme

3.4 Using concentrations of solutions in mol/dm3 Questions

  1. GCSE
  2. /Chemistry
  3. /3.4 Using concentrations of solutions in mol/dm3

106 exam-style questions on AQA GCSE Chemistry 3.4 Using concentrations of solutions in mol/dm3, covering 3.4.1 Concentration in mol/dm3. Each one has a worked solution and a mark scheme showing where the marks go.

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