In a titration, 30.0 cm3 of 0.0800 mol/dm3 potassium hydroxide solution is exactly neutralised by 20.0 cm3 of nitric acid. The equation is KOH+HNO3→KNO3+H2O\text{KOH} + \text{HNO}_3 \rightarrow \text{KNO}_3 + \text{H}_2\text{O}KOH+HNO3→KNO3+H2O. What is the concentration of the nitric acid?
0.0800 mol/dm30.0800\ \text{mol/dm}^30.0800 mol/dm3
0.0533 mol/dm30.0533\ \text{mol/dm}^30.0533 mol/dm3
0.000120 mol/dm30.000120\ \text{mol/dm}^30.000120 mol/dm3
0.120 mol/dm30.120\ \text{mol/dm}^30.120 mol/dm3
106 exam-style questions on AQA GCSE Chemistry 3.4 Using concentrations of solutions in mol/dm3, covering 3.4.1 Concentration in mol/dm3. Each one has a worked solution and a mark scheme showing where the marks go.