Hydrogen iodide forms in the reversible reaction shown.
H2(g)+I2(g)⇌2HI(g)\text{H}_2\text{(g)} + \text{I}_2\text{(g)} \rightleftharpoons 2\text{HI(g)}H2(g)+I2(g)⇌2HI(g)
The concentration of iodine is increased at constant temperature.
What is the effect on the equilibrium yield of hydrogen iodide?
The yield decreases because the reverse reaction is favoured by the added iodine
The yield stays the same because both reaction rates eventually become equal again
The yield stays the same because both sides contain the same number of gas molecules
The yield increases because the equilibrium moves right to use some of the added iodine
109 exam-style questions on AQA GCSE Chemistry 6.2 Reversible reactions and dynamic equilibrium, covering 6.2.1 Reversible reactions, 6.2.2 Energy changes and reversible reactions, 6.2.3 Equilibrium, 6.2.4 The effect of changing conditions on equilibrium, 6.2.5 The effect of changing concentration, 6.2.6 The effect of temperature changes on equilibrium, and 6.2.7 The effect of pressure changes on equilibrium. Each one has a worked solution and a mark scheme showing where the marks go.