A reaction forms a dissolved product. The amount of product was plotted against time. A tangent was drawn to the curve at 80 s.
Two points on the tangent are shown in the table.
| Time in s\text{s}s | Amount of product in mol\text{mol}mol |
|---|---|
| 50 | 0.0200 |
| 110 | 0.0350 |
Calculate the rate of reaction at 80 s.
The mean rate of reaction during the first 80 s was 0.000344 mol/s.
Compare the rate at 80 s with the mean rate during the first 80 s. Explain why the rates are different.
127 exam-style questions on AQA GCSE Chemistry 6.1 Rate of reaction, covering 6.1.1a Calculating rates of reactions, 6.1.1b Gradient of a tangent as rate, 6.1.2 Factors which affect the rates of chemical reactions, 6.1.3 Collision theory and activation energy, and 6.1.4 Catalysts. Each one has a worked solution and a mark scheme showing where the marks go.