A researcher investigated the rate of decomposition of hydrogen peroxide in the presence of a yeast suspension as a source of catalase. Oxygen gas was collected over water. The researcher performed four trials and calculated the rate of oxygen gas production for each trial. The results are shown in the table below.
| Trial | Rate of oxygen production in cm3/s\text{cm}^3/\text{s}cm3/s |
|---|---|
| Trial 1 | 1.85 |
| Trial 2 | 1.15 |
| Trial 3 | 1.82 |
| Trial 4 | 1.73 |
Determine the mean time taken to collect 72 cm372\text{ cm}^372 cm3 of oxygen gas. Do not include any anomalous results in your calculation.
Use the equation:
mean rate of reaction=volume of gas collectedmean time taken \text{mean rate of reaction} = \frac{\text{volume of gas collected}}{\text{mean time taken}} mean rate of reaction=mean time takenvolume of gas collected26 exam-style questions on AQA GCSE Chemistry 6.1 Rate of reaction, covering 6.1.1 Calculating rates of reactions, 6.1.2 Factors which affect the rates of chemical reactions, 6.1.3 Collision theory and activation energy, and 6.1.4 Catalysts. Each one has a worked solution and a mark scheme showing where the marks go.