Quadratics

What you'll learn

How to recognise a quadratic and connect its equation to its graph.
How the discriminant tells you whether roots are real, repeated, or absent.
How to complete the square to find turning points and prove inequalities.
How quadratics appear in tangency, projectile, and profit-style modelling questions.

1. Quadratic basics

Definition

Quadratic expression

A quadratic expression in $x$ is an expression of the form $ax^2+bx+c$ , where $a$ , $b$ and $c$ are constants and $a≠0a\neq0$ . The number $a$ is the coefficient of $x^2$ , $b$ is the coefficient of $x$ , and $c$ is the constant term.

A quadratic equation is made by setting a quadratic expression equal to zero, for example $ax^2+bx+c=0$ .

A root or solution is a value of $x$ that makes the equation true. On the graph of $y=ax^2+bx+c$ , roots are the points where the curve crosses or touches the $x$ -axis.

The graph of a quadratic is called a parabola. If $a > 0$ , it opens upwards. If $a < 0$ , it opens downwards.

Two labelled parabolas showing how the sign of the coefficient of x² determines whether the graph opens upwards or downwards.

Example

Putting a quadratic into standard form

Rewrite $3x^2+7=2x$ in the form $ax^2+bx+c=0$ and identify $a$ , $b$ and $c$ .

Move every term to the left-hand side:
$3x^2-2x+7=0$
Compare this with $ax^2+bx+c=0$ .
The values are $a = 3$ , $b = - 2$ and $c = 7$ .

2. The discriminant

Definition

Discriminant

For a quadratic equation $ax^2+bx+c=0$ , the discriminant is

Δ=b2−4ac\Delta=b^2-4ac

It tells you how many real roots the equation has.

Key Idea

What the discriminant tells you

If $Δ>0\Delta>0$ , there are two distinct real roots.
If $Δ=0\Delta=0$ , there is one repeated root, also called equal roots.
If $Δ<0\Delta<0$ , there are no real roots.

The word distinct means “different”. A repeated root means the graph just touches the $x$ -axis at its turning point.

The three discriminant cases shown as parabolas with two real roots, one repeated root, and no real roots.

Three parabolas showing the discriminant cases: two roots, repeated root, and no real roots

Example

Showing there are no real roots

Show that $2x^2+5=4x$ has no real roots.

Put the equation into standard form:
$2x^2-4x+5=0$
Identify the coefficients: $a = 2$ , $b = - 4$ and $c = 5$ .
Calculate the discriminant:
$Δ=(−4)2−4(2)(5)=16−40=−24\Delta=(-4)^2-4(2)(5)=16-40=-24$
Since $Δ<0\Delta<0$ , the equation has no real roots.

Example

Equal roots with a positive parameter

The equation $kx^2+8x+2k=0$ , where $k$ is positive, has equal roots. Find $k$ .

Equal roots means $Δ=0\Delta=0$ .
Substitute $a = k$ , $b = 8$ and $c = 2 k$ :
$8^2-4(k)(2k)=0$
Solve for $k$ :
$64−8k2=0⇒k2=8⇒k=±2264-8k^2=0 \Rightarrow k^2=8 \Rightarrow k=\pm2\sqrt2$
Since $k$ is positive, $k=22k=2\sqrt2$ .

3. Parameter ranges and hidden edge cases

Many AS questions ask for a set of values of a constant. That usually means you will form an inequality using the discriminant.

Common Mistake

Check it is still a quadratic

The discriminant rules apply to quadratics, so you need $a≠0a\neq0$ . If the coefficient of $x^2$ contains a parameter, check whether it could become zero.

Example

Finding a parameter range

Find the values of $k$ for which $k+1)x^2+2x+k=0$ has two distinct real roots.

A number line for the parameter k showing the interval where the quadratic inequality is satisfied and the excluded value k = -1.

For a genuine quadratic, the coefficient of $x^2$ must not be zero, so $k≠−1k\neq-1$ .
Two distinct real roots means $Δ>0\Delta>0$ :
$2^2-4(k+1)k>0$
Simplify the inequality:
$4−4k2−4k>0⇒k2+k−1<04-4k^2-4k>0 \Rightarrow k^2+k-1<0$
Find the critical values by solving $k^2+k-1=0$ :
$k=−1±52k=\frac{-1\pm\sqrt5}{2}$
Since $k^2+k-1$ is negative between its roots, and $k = - 1$ must be excluded:
$−1−52<k<−1or−1<k<−1+52\frac{-1-\sqrt5}{2}<k<-1 \quad \text{or} \quad -1<k<\frac{-1+\sqrt5}{2}$

Common Mistake

Forgetting the excluded value

If $a$ contains the parameter, do not just solve $Δ>0\Delta>0$ , $Δ=0\Delta=0$ or $Δ<0\Delta<0$ . First check whether the equation stops being quadratic for any value of the parameter.

4. Completing the square

Definition

Completed-square form

Completing the square means rewriting a quadratic in the form $a(x-h)^2+k$ . This form shows the turning point clearly.

If a quadratic is written as $y=a(x-h)^2+k$ , its turning point is $(h, k)$ . If it is written as $y=a(x+b)^2+c`, its turning point is$ (-b,c)$.

The turning point is the minimum point if $a > 0$ , and the maximum point if $a < 0$ . The vertical line through the turning point is called the axis of symmetry.

Completed-square form identifies the vertex and axis of symmetry directly from y = a(x − h)² + k.

Completed-square form showing the vertex and axis of symmetry

Tip

Completing the square shortcut

For $x^2+px$ , halve the coefficient of $x$ , put it inside the bracket, then subtract the square you accidentally added.

Example

Finding the turning point

Express $3x^2+12x+5$ in completed-square form and state the turning point.

The graph of y = 3(x + 2)² − 7 showing its minimum point at (−2, −7) and axis of symmetry x = −2.

Factor 3 from the $x^2$ and $x$ terms:
$3x^2+12x+5=3(x^2+4x)+5$
Complete the square inside the bracket:
$x^2+4x=(x+2)^2-4$
Substitute this back in:
$3((x+2)2−4)+5=3(x+2)2−73\left((x+2)^2-4\right)+5=3(x+2)^2-7$
The completed-square form is $3(x+2)^2-7$ , so the minimum point is $(- 2, - 7)$ .

At the minimum or maximum point of a quadratic, the tangent is horizontal. So the normal at that point is vertical, with equation $x-coordinatex=\text{turning point }x\text{-coordinate}$ .

5. Solving by completing the square

Completing the square can also be used to solve equations exactly, especially when a question asks for roots “in terms of” a parameter.

Example

Roots in terms of a parameter

By completing the square, find the roots of $x^2+px+7=0$ .

Complete the square:
$x2+px+7=(x+p2)2+7−p24x^2+px+7=\left(x+\frac{p}{2}\right)^2+7-\frac{p^2}{4}$
Set the expression equal to zero:
$(x+p2)2=p24−7\left(x+\frac{p}{2}\right)^2=\frac{p^2}{4}-7$
Write the right-hand side as a single fraction:
$(x+p2)2=p2−284\left(x+\frac{p}{2}\right)^2=\frac{p^2-28}{4}$
Square root both sides:
$x+p2=±p2−282x+\frac{p}{2}=\pm\frac{\sqrt{p^2-28}}{2}$
Therefore the roots are:
$x=−p±p2−282x=\frac{-p\pm\sqrt{p^2-28}}{2}$

6. Proving quadratic inequalities

A square is always non-negative: $(x−h)2≥0(x-h)^2\ge0$ for all real $x$ . This makes completed-square form very useful for proving that an expression is always positive.

Example

Proving an inequality for all real values

Prove that $x^2+3x+10>x+1$ for all real $x$ .

Move everything to the left-hand side:
$x2+3x+10−(x+1)>0⇒x2+2x+9>0x^2+3x+10-(x+1)>0 \Rightarrow x^2+2x+9>0$
Complete the square:
$x^2+2x+9=(x+1)^2+8$
Since $(x+1)2≥0(x+1)^2\ge0$ , the expression $x+1)^2+8$ is always at least 8.
Therefore $x^2+3x+10>x+1$ for all real $x$ .

7. Intersections, tangents and models

A tangent is a line that touches a curve at exactly one point locally. Algebraically, tangency often means the equation formed by setting the line and curve equal has a repeated root.

Tangency corresponds to a single repeated solution when a line just touches a curve.

Example

Finding tangency values

The curve $y=3x+ky=\frac{3}{x}+k$ , where $x≠0x\neq0$ , meets the line $y = - x + 4$ . Find the values of $k$ for which the line is a tangent to the curve.

The given line can be tangent to different vertical shifts of the curve y = 3/x + k.

Set the two expressions for $y$ equal:
$3x+k=−x+4\frac{3}{x}+k=-x+4$
Multiply by $x$ :
$3+kx=-x^2+4x$
Rearrange into quadratic form:
$x^2+(k-4)x+3=0$
For tangency, this quadratic has a repeated root, so $Δ=0\Delta=0$ :
$k-4)^2-4(1)(3)=0$
Solve for $k$ :
$(k−4)2=12⇒k=4±23(k-4)^2=12 \Rightarrow k=4\pm2\sqrt3$

Quadratic models often use completed-square form directly. The domain is the set of input values where the model makes sense.

Example

Using a profit model

A club models profit using $P=50-2(x-12)^2$ , where $P$ is profit in thousands of pounds and $x$ is the ticket price in pounds. Find the maximum profit and the prices giving profit more than £32,000.

The profit model is a downward-opening parabola with maximum profit at x = 12 and profit above £32,000 between x = 9 and x = 15.

Since $2(x−12)2≥02(x-12)^2\ge0$ and is subtracted from 50, the maximum value is $P = 50$ when $x = 12$ .
So the maximum profit is £50,000, at a ticket price of £12.
Profit more than £32,000 means $P > 32$ :
$50-2(x-12)^2>32$
Solve the inequality:
$x-12)^2<9$
Convert this to a range:
$\Rightarrow 9<x<15$
The model predicts profit above £32,000 for ticket prices between £9 and £15, not including the endpoints.

Exam technique

In the exam

Put the equation into $ax^2+bx+c=0$ before using the discriminant.
Translate the wording carefully: two distinct roots means $Δ>0\Delta>0$ , repeated roots or tangent means $Δ=0\Delta=0$ , and no real roots means $\Delta<0`.
If a coefficient contains a parameter, check whether the equation can stop being quadratic.
For completed-square form, read the turning point directly and use the sign of $a$ to decide minimum or maximum.
In modelling questions, mention sensible restrictions such as positive speeds, positive prices, or values within the context.

Self review

Check yourself

Can you explain why $x-3)^2+5=0$ has no real roots?
If $k-2)x^2+4x+1=0$ has two distinct real roots, what extra value of $k$ must you remember to check?
In $4(x+1)^2-7$ , where is the turning point, and is it a minimum or maximum?

What you'll learn

How to recognise a quadratic and connect its equation to its graph.
How the discriminant tells you whether roots are real, repeated, or absent.
How to complete the square to find turning points and prove inequalities.
How quadratics appear in tangency, projectile, and profit-style modelling questions.

1. Quadratic basics

Definition

Quadratic expression

A quadratic equation is made by setting a quadratic expression equal to zero, for example $ax^2+bx+c=0$ .

A root or solution is a value of $x$ that makes the equation true. On the graph of $y=ax^2+bx+c$ , roots are the points where the curve crosses or touches the $x$ -axis.

The graph of a quadratic is called a parabola. If $a > 0$ , it opens upwards. If $a < 0$ , it opens downwards.

Two labelled parabolas showing how the sign of the coefficient of x² determines whether the graph opens upwards or downwards.

Example

Putting a quadratic into standard form

Rewrite $3x^2+7=2x$ in the form $ax^2+bx+c=0$ and identify $a$ , $b$ and $c$ .

Move every term to the left-hand side:
$3x^2-2x+7=0$
Compare this with $ax^2+bx+c=0$ .
The values are $a = 3$ , $b = - 2$ and $c = 7$ .

2. The discriminant

Definition

Discriminant

For a quadratic equation $ax^2+bx+c=0$ , the discriminant is

Δ=b2−4ac\Delta=b^2-4ac

It tells you how many real roots the equation has.

Key Idea

What the discriminant tells you

If $Δ>0\Delta>0$ , there are two distinct real roots.
If $Δ=0\Delta=0$ , there is one repeated root, also called equal roots.
If $Δ<0\Delta<0$ , there are no real roots.

The word distinct means “different”. A repeated root means the graph just touches the $x$ -axis at its turning point.

The three discriminant cases shown as parabolas with two real roots, one repeated root, and no real roots.

Three parabolas showing the discriminant cases: two roots, repeated root, and no real roots

Example

Showing there are no real roots

Show that $2x^2+5=4x$ has no real roots.

Put the equation into standard form:
$2x^2-4x+5=0$
Identify the coefficients: $a = 2$ , $b = - 4$ and $c = 5$ .
Calculate the discriminant:
$Δ=(−4)2−4(2)(5)=16−40=−24\Delta=(-4)^2-4(2)(5)=16-40=-24$
Since $Δ<0\Delta<0$ , the equation has no real roots.

Example

Equal roots with a positive parameter

The equation $kx^2+8x+2k=0$ , where $k$ is positive, has equal roots. Find $k$ .

Equal roots means $Δ=0\Delta=0$ .
Substitute $a = k$ , $b = 8$ and $c = 2 k$ :
$8^2-4(k)(2k)=0$
Solve for $k$ :
$64−8k2=0⇒k2=8⇒k=±2264-8k^2=0 \Rightarrow k^2=8 \Rightarrow k=\pm2\sqrt2$
Since $k$ is positive, $k=22k=2\sqrt2$ .

3. Parameter ranges and hidden edge cases

Many AS questions ask for a set of values of a constant. That usually means you will form an inequality using the discriminant.

Common Mistake

Check it is still a quadratic

The discriminant rules apply to quadratics, so you need $a≠0a\neq0$ . If the coefficient of $x^2$ contains a parameter, check whether it could become zero.

Example

Finding a parameter range

Find the values of $k$ for which $k+1)x^2+2x+k=0$ has two distinct real roots.

A number line for the parameter k showing the interval where the quadratic inequality is satisfied and the excluded value k = -1.

For a genuine quadratic, the coefficient of $x^2$ must not be zero, so $k≠−1k\neq-1$ .
Two distinct real roots means $Δ>0\Delta>0$ :
$2^2-4(k+1)k>0$
Simplify the inequality:
$4−4k2−4k>0⇒k2+k−1<04-4k^2-4k>0 \Rightarrow k^2+k-1<0$
Find the critical values by solving $k^2+k-1=0$ :
$k=−1±52k=\frac{-1\pm\sqrt5}{2}$
Since $k^2+k-1$ is negative between its roots, and $k = - 1$ must be excluded:
$−1−52<k<−1or−1<k<−1+52\frac{-1-\sqrt5}{2}<k<-1 \quad \text{or} \quad -1<k<\frac{-1+\sqrt5}{2}$

Common Mistake

Forgetting the excluded value

If $a$ contains the parameter, do not just solve $Δ>0\Delta>0$ , $Δ=0\Delta=0$ or $Δ<0\Delta<0$ . First check whether the equation stops being quadratic for any value of the parameter.

4. Completing the square

Definition

Completed-square form

Completing the square means rewriting a quadratic in the form $a(x-h)^2+k$ . This form shows the turning point clearly.

If a quadratic is written as $y=a(x-h)^2+k$ , its turning point is $(h, k)$ . If it is written as $y=a(x+b)^2+c`, its turning point is$ (-b,c)$.

The turning point is the minimum point if $a > 0$ , and the maximum point if $a < 0$ . The vertical line through the turning point is called the axis of symmetry.

Completed-square form identifies the vertex and axis of symmetry directly from y = a(x − h)² + k.

Completed-square form showing the vertex and axis of symmetry

Tip

Completing the square shortcut

For $x^2+px$ , halve the coefficient of $x$ , put it inside the bracket, then subtract the square you accidentally added.

Example

Finding the turning point

Express $3x^2+12x+5$ in completed-square form and state the turning point.

The graph of y = 3(x + 2)² − 7 showing its minimum point at (−2, −7) and axis of symmetry x = −2.

Factor 3 from the $x^2$ and $x$ terms:
$3x^2+12x+5=3(x^2+4x)+5$
Complete the square inside the bracket:
$x^2+4x=(x+2)^2-4$
Substitute this back in:
$3((x+2)2−4)+5=3(x+2)2−73\left((x+2)^2-4\right)+5=3(x+2)^2-7$
The completed-square form is $3(x+2)^2-7$ , so the minimum point is $(- 2, - 7)$ .

At the minimum or maximum point of a quadratic, the tangent is horizontal. So the normal at that point is vertical, with equation $x-coordinatex=\text{turning point }x\text{-coordinate}$ .

5. Solving by completing the square

Completing the square can also be used to solve equations exactly, especially when a question asks for roots “in terms of” a parameter.

Example

Roots in terms of a parameter

By completing the square, find the roots of $x^2+px+7=0$ .

Complete the square:
$x2+px+7=(x+p2)2+7−p24x^2+px+7=\left(x+\frac{p}{2}\right)^2+7-\frac{p^2}{4}$
Set the expression equal to zero:
$(x+p2)2=p24−7\left(x+\frac{p}{2}\right)^2=\frac{p^2}{4}-7$
Write the right-hand side as a single fraction:
$(x+p2)2=p2−284\left(x+\frac{p}{2}\right)^2=\frac{p^2-28}{4}$
Square root both sides:
$x+p2=±p2−282x+\frac{p}{2}=\pm\frac{\sqrt{p^2-28}}{2}$
Therefore the roots are:
$x=−p±p2−282x=\frac{-p\pm\sqrt{p^2-28}}{2}$

6. Proving quadratic inequalities

A square is always non-negative: $(x−h)2≥0(x-h)^2\ge0$ for all real $x$ . This makes completed-square form very useful for proving that an expression is always positive.

Example

Proving an inequality for all real values

Prove that $x^2+3x+10>x+1$ for all real $x$ .

Move everything to the left-hand side:
$x2+3x+10−(x+1)>0⇒x2+2x+9>0x^2+3x+10-(x+1)>0 \Rightarrow x^2+2x+9>0$
Complete the square:
$x^2+2x+9=(x+1)^2+8$
Since $(x+1)2≥0(x+1)^2\ge0$ , the expression $x+1)^2+8$ is always at least 8.
Therefore $x^2+3x+10>x+1$ for all real $x$ .

7. Intersections, tangents and models

A tangent is a line that touches a curve at exactly one point locally. Algebraically, tangency often means the equation formed by setting the line and curve equal has a repeated root.

Tangency corresponds to a single repeated solution when a line just touches a curve.

Example

Finding tangency values

The curve $y=3x+ky=\frac{3}{x}+k$ , where $x≠0x\neq0$ , meets the line $y = - x + 4$ . Find the values of $k$ for which the line is a tangent to the curve.

The given line can be tangent to different vertical shifts of the curve y = 3/x + k.

Set the two expressions for $y$ equal:
$3x+k=−x+4\frac{3}{x}+k=-x+4$
Multiply by $x$ :
$3+kx=-x^2+4x$
Rearrange into quadratic form:
$x^2+(k-4)x+3=0$
For tangency, this quadratic has a repeated root, so $Δ=0\Delta=0$ :
$k-4)^2-4(1)(3)=0$
Solve for $k$ :
$(k−4)2=12⇒k=4±23(k-4)^2=12 \Rightarrow k=4\pm2\sqrt3$

Quadratic models often use completed-square form directly. The domain is the set of input values where the model makes sense.

Example

Using a profit model

The profit model is a downward-opening parabola with maximum profit at x = 12 and profit above £32,000 between x = 9 and x = 15.

Since $2(x−12)2≥02(x-12)^2\ge0$ and is subtracted from 50, the maximum value is $P = 50$ when $x = 12$ .
So the maximum profit is £50,000, at a ticket price of £12.
Profit more than £32,000 means $P > 32$ :
$50-2(x-12)^2>32$
Solve the inequality:
$x-12)^2<9$
Convert this to a range:
$\Rightarrow 9<x<15$
The model predicts profit above £32,000 for ticket prices between £9 and £15, not including the endpoints.

Exam technique

In the exam

Put the equation into $ax^2+bx+c=0$ before using the discriminant.
Translate the wording carefully: two distinct roots means $Δ>0\Delta>0$ , repeated roots or tangent means $Δ=0\Delta=0$ , and no real roots means $\Delta<0`.
If a coefficient contains a parameter, check whether the equation can stop being quadratic.
For completed-square form, read the turning point directly and use the sign of $a$ to decide minimum or maximum.
In modelling questions, mention sensible restrictions such as positive speeds, positive prices, or values within the context.

Self review

Check yourself

Can you explain why $x-3)^2+5=0$ has no real roots?
If $k-2)x^2+4x+1=0$ has two distinct real roots, what extra value of $k$ must you remember to check?
In $4(x+1)^2-7$ , where is the turning point, and is it a minimum or maximum?

What you'll learn

1. Quadratic basics

2. The discriminant

3. Parameter ranges and hidden edge cases

4. Completing the square

5. Solving by completing the square

6. Proving quadratic inequalities

7. Intersections, tangents and models

Recap questions

Review Quadratics by teaching Genie

Recap your knowledge with an interactive lesson

Remember key concepts with flashcards

Quadratics

What you'll learn

1. Quadratic basics

2. The discriminant

3. Parameter ranges and hidden edge cases

4. Completing the square

5. Solving by completing the square

6. Proving quadratic inequalities

7. Intersections, tangents and models

Recap questions

Review Quadratics by teaching Genie

Recap your knowledge with an interactive lesson

Remember key concepts with flashcards

Quadratics

What you'll learn

1. Quadratic basics

2. The discriminant

3. Parameter ranges and hidden edge cases

4. Completing the square

5. Solving by completing the square

6. Proving quadratic inequalities

7. Intersections, tangents and models

Recap questions

Review Quadratics by teaching Genie

Recap your knowledge with an interactive lesson

Remember key concepts with flashcards

Quadratics Revision Guide

Quadratics

What you'll learn

1. Quadratic basics

2. The discriminant

3. Parameter ranges and hidden edge cases

4. Completing the square

5. Solving by completing the square

6. Proving quadratic inequalities

7. Intersections, tangents and models

Recap questions

Review Quadratics by teaching Genie

Recap your knowledge with an interactive lesson

Remember key concepts with flashcards

Quadratics Revision Guide