Given that k k\,k is a constant
Find ∫(kx3+2x)dx\displaystyle \int \left( \frac{k}{x^3} + 2x \right) dx∫(x3k+2x)dx Giving your answer in its simplest form.
Find the value of k k\,k such that ∫12(kx3+2x)dx=12\displaystyle \int_1^2 \left( \frac{k}{x^3} + 2x \right) dx = 12∫12(x3k+2x)dx=12
51 exam-style questions on Edexcel AS Level Maths Integration, covering 13.1 Integrating x^n, 13.2 Indefinite Integrals, 13.3 Finding Functions, 13.4 Definite Integrals, 13.5 Areas under Curves, 13.6 Areas under the x-axis, and 13.7 Areas between curves and lines. Each one has a worked solution and a mark scheme showing where the marks go.