The acceleration of a particle after t t\,t seconds is given by (4t−8) ms−2(4t - 8) \text{ ms}^{-2}(4t−8) ms−2. Given the velocity (vvv) of the particle is 6 ms-1 when t=0t = 0t=0.
Find v v\,v in terms of ttt.
Find the distance between the two points the particle is instantaneously at rest.
28 exam-style questions on Edexcel AS Level Maths Variable Acceleration, covering 11.1 Functions of Time, 11.2 Using Differentiation, 11.3 Maxima and Minima Problems, 11.4 Using Integration, and 11.5 Constant Acceleration Formulae. Each one has a worked solution and a mark scheme showing where the marks go.